Solving Vector Resultants: Magnitude & Direction

  • Thread starter anglum
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In summary, the problem involves finding the magnitude and direction of the resultant displacement from a starting point after traveling certain distances and angles. By using the x and y components and the Pythagorean theorem, the resultant displacement is found to be 279.409 paces west. The y components are adjusted to account for the negative direction, resulting in a magnitude of 11.68 paces north. The direction of the resultant displacement is in the counterclockwise direction from due east at an angle of 45.16 degrees.
  • #1
anglum
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vector resultants? please help...

Homework Statement



go 83.9 paces at 188 degrees

turn to 128 degrees and walk 199 paces

then travel 73 paces at 179 degreess

find the magnitude of the resultant displacement from the starting point, answer in units of paces.

and what is the direction of the resultant displacement? use counterclockwise from due east as the positive angular direction between the limits of-180 degrees and +180 degrees. answer in units of degrees.

Homework Equations





The Attempt at a Solution



i have found the x components to be all in teh west direction with the values being
i got these by takin the distance times the cos of the angle
a to b = -83.9
b to c = -122.52
c to d = -72.989

with the resultant being 279.409 west

y components
i got these by taking the distance times the sin of the angle
a to b = -11.68 south
b to c = 156.87 north
c to d = 1.27 north

not sure what the resultant comes to? please help

once i get both resultants correct i use the pythagorean theorem to get the reultant for the distance from a(starting point) to d (ending point) correct?
 
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  • #2
Yeah... what youre doing is correct. -11.68 south is equal to 11.68 north. That should help. Do what you did earlier.
 
  • #3




Dear student,

Thank you for reaching out for help with your problem. It looks like you are on the right track with your calculations for the x and y components. To find the magnitude of the resultant, you can use the Pythagorean theorem as you mentioned. The formula is:

R = √(Rx^2 + Ry^2)

Where R is the magnitude of the resultant, Rx is the x component, and Ry is the y component. Plugging in your values, we get:

R = √((279.409)^2 + (146.45)^2) = 320.58 paces

So the magnitude of the resultant displacement from the starting point is 320.58 paces.

To find the direction of the resultant, we can use the inverse tangent function. The formula is:

θ = tan^-1(Ry/Rx)

Where θ is the direction of the resultant, Rx is the x component, and Ry is the y component. Plugging in your values, we get:

θ = tan^-1(146.45/279.409) = 27.38 degrees

Since the question asks for the direction in units of degrees, we can round to the nearest degree, giving us a direction of 27 degrees counterclockwise from due east.

I hope this helps you with your problem. Good luck with your studies!

Sincerely,
 

Related to Solving Vector Resultants: Magnitude & Direction

1. What is a vector resultant?

A vector resultant is the total vector sum of two or more individual vectors. It represents the overall magnitude and direction of the combined vectors.

2. How do you calculate the magnitude of a vector resultant?

To calculate the magnitude of a vector resultant, you can use the Pythagorean theorem, which states that the magnitude (or length) of a vector is equal to the square root of the sum of the squares of its components.

3. How do you determine the direction of a vector resultant?

The direction of a vector resultant can be determined by finding the angle between the resultant vector and a known reference axis, such as the x-axis or y-axis. This can be done using trigonometric functions such as sine, cosine, and tangent.

4. What is the difference between a scalar and a vector resultant?

A scalar resultant only has a magnitude, while a vector resultant has both magnitude and direction. Scalars are represented by a single number, while vectors are represented by both a magnitude and a direction.

5. Can you have a vector resultant with a negative magnitude?

Yes, a vector resultant can have a negative magnitude if the vectors being added have opposite directions. In this case, the resultant vector would have a magnitude that is smaller than either of the individual vectors, and its direction would be in the direction of the larger vector.

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