Solving the Inclined Plane Homework Problem

In summary, we have a problem involving an inclined plane, a book with a coefficient of kinetic friction of 0.16, and a distance of 4.9 m. Using Newton's second law and kinematics equations, we can determine the time it takes for the book to reach the bottom of the incline by finding the acceleration and solving for t.
  • #1
rechitzy
21
0

Homework Statement



An inclined plane at 30.0° is 4.9 m long. A book which has a coefficient of kinetic friction with the inclined plane of 0.16 is placed at the top and immediately begins to slide. How long will it take for the book to reach the bottom of the incline?


Homework Equations



a=mg sin(angle)-coeff of kinetic friction cos(angle)

t2= Xf/(1/2)(a)


The Attempt at a Solution



i tried it and i have had different answers every time due to some mistakes, but i have only one attempt left.
 
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  • #2
Ok, first you need to draw a force diagram for the object.

The book has a normal force exerted by the incline on the book. It has a component of gravity in the direction perpendicular to the incline. It has a component of gravity in the direction parallel to the incline. There is a force of friction acting on the book due to the incline and points in the direction opposite to the force of gravity parallel to the incline.

This problem involves friction. It is important to know the normal force in all friction problems so let's find that first.

You know the book is not floating off the incline so the normal force which points in a direction perpendicular to the incline must equal the component of gravity pointing in the opposite direction. Therefore,

N = mgcos30 and Fric = 0.16mgcos30

This force of friction opposes the force of gravity acting parallel to the incline, so Newton's second law in the direction parallel to the incline gives us

mgsin30 - Fric = ma

We know Fric from earlier.

mgsin30 - 0.16mgcos30 = ma

Notice all terms have a "m". Cancel them out.

gsin30 - 0.16gcos30 = a

Solve for your acceleration.

The book has no initial velocity, and is displaced 4.9 m. By kinematics,

4.9 = 0.5at2

You know a from earlier, so solve for t.
 

Related to Solving the Inclined Plane Homework Problem

What is an inclined plane?

An inclined plane is a simple machine that consists of a flat surface that is angled to make it easier to move objects from one point to another. It is commonly referred to as a ramp.

How do you solve the inclined plane homework problem?

To solve the inclined plane homework problem, you will need to use the formula F = mgsinθ, where F is the force required to move the object, m is the mass of the object, g is the acceleration due to gravity (9.8 m/s²), and θ is the angle of inclination. You can also use the formula F = μmgcosθ, where μ is the coefficient of friction.

What are the steps to solve the inclined plane homework problem?

The steps to solve the inclined plane homework problem are as follows:
1. Identify the given values, including the mass of the object, the angle of inclination, and the coefficient of friction (if given).
2. Determine the formula to use based on the given information.
3. Substitute the values into the formula.
4. Solve for the force required to move the object.
5. Check your answer and make sure it is in the correct units.

Can the inclined plane homework problem be solved without using formulas?

No, the inclined plane homework problem cannot be solved without using formulas. The formulas provide a mathematical relationship between the different variables involved in the problem. Without using these formulas, it would be difficult to accurately solve the problem.

How can I check my answer for the inclined plane homework problem?

To check your answer for the inclined plane homework problem, you can use the formula F = mgsinθ or F = μmgcosθ (depending on which one you used to solve the problem) and plug in your calculated force value. Then, compare the result to the given values for mass, angle of inclination, and coefficient of friction. If they match, then your answer is correct.

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