- #1
gillgill
- 128
- 0
1) │3x-2│<= x+1 ; x>=-1
Case1: 3x-2>=0
x>= 2/3
3x-2<=x+1
x<=3/2
what is case 2?
2) │2-3x│ < 3x-4
3) │x-3│=x-2
How do u solve these?
Case1: 3x-2>=0
x>= 2/3
3x-2<=x+1
x<=3/2
what is case 2?
2) │2-3x│ < 3x-4
3) │x-3│=x-2
How do u solve these?