- #1
Yomna
- 5
- 0
Hey People...um this is a question i got for school...i know what was used to solve it but i can't understand how that method was used and why they did that...
it says:
A foundry operator finds that it takes 55.3MJ of heat to heat a 286 kg mass of an alloy steel from 22 degrees C to 452 degrees C.
The first thing they ask us is to find the specific heat capacity for the steel...which is pretty straight forward..:
c= Q/m*delta T
Q= 55.3 MJ
m=286
delta T=430
(55.3*10^6)/(430*286)
=4.5*10^2 J per Kg per kelvin..
The next bit is what's bothering me...
it says:
If the foundry worker cools the steel by pouring water onto it, the water will heat up to its boiling point, then it will boil. What minimum mass of water, initially at 22 degrees C, would cool the hot steel down to 100 degrees C?
I really don't know what to do here...
Can someone please help? and like..explain?
Thank u so much.
Yomna
it says:
A foundry operator finds that it takes 55.3MJ of heat to heat a 286 kg mass of an alloy steel from 22 degrees C to 452 degrees C.
The first thing they ask us is to find the specific heat capacity for the steel...which is pretty straight forward..:
c= Q/m*delta T
Q= 55.3 MJ
m=286
delta T=430
(55.3*10^6)/(430*286)
=4.5*10^2 J per Kg per kelvin..
The next bit is what's bothering me...
it says:
If the foundry worker cools the steel by pouring water onto it, the water will heat up to its boiling point, then it will boil. What minimum mass of water, initially at 22 degrees C, would cool the hot steel down to 100 degrees C?
I really don't know what to do here...
Can someone please help? and like..explain?
Thank u so much.
Yomna