mysticbms said:Homework Statement
Solve for g in terms of d, t, and theta on an inclined plane.
Homework Equations
Fnet=ma and d=Vit + .5a*t^2
The Attempt at a Solution
Solving for a on an inclined plane I get g*sin theta.
Using the equation for constant acceleration d=Vit + .5a*t^2 I solve for g.
Vi is 0 on an initial plane so I have d=.5(g*sin theta)t^2
g=2d/(sin theta*t^2)
Is this correct?
An inclined plane is a flat surface that is tilted at an angle, which allows objects to move up or down with less force than if they were on a flat surface.
The formula for solving for g on an inclined plane is g = sinθ, where θ is the angle of the inclined plane.
An inclined plane allows us to break down the force of gravity into two components - the normal force (perpendicular to the plane) and the parallel force (down the plane). This makes it easier to calculate the acceleration due to gravity (g) without any other external forces affecting the object.
The value of g on an inclined plane is affected by the angle of the inclined plane, the mass of the object, and the coefficient of friction between the object and the plane.
No, g is a constant value and is always equal to 9.8 m/s^2 on Earth, regardless of the angle of the inclined plane.