- #1
NewtonianAlch
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Homework Statement
I am a little confused on the steps to take to solve these kinds of functions.
Solve:
cosh z = 2i
The Attempt at a Solution
We were given identities for sinh z = 0 and cosh z = 0 and also other identities like
cosh(z) = cos (iz)
So cos (iz) = 2i
cos (z) would be 2i for (Pi/2 + 2kPi) right? So cos(iz) = i(Pi/2 + 2kPi) = 2i?
However, this doesn't look right.