Solving Collisions with angles problem

[AceInfinity]

First off, i'd like to note that this isn't homework, and I've seen other threads in here that deal with question/equation/problems, so I hope this isn't against the rules. I found this on a practice physics test online. I'm just using it for the benefit of my knowledge, nothing more.

I can provide the link if necessary for proof.

Heres the question I want to know how to solve:
[PLAIN]http://k.min.us/ibDXoi.jpg

 

[tiny-tim]

Hi AceInfinity!

As you know, you need to use conservation of https://www.physicsforums.com/library.php?do=view_item&itemid=53".

Momentum is a vector, so this is a vector equation, which means the components of momentum in any direction are conserved.

So choose a suitable direction ……

what do you get? ​

 

[AceInfinity]

ohhh... I think you put me on the right track for beginning to solve this. The initial momentum was

in this case. Therefore the conservation of momentum is seen for that X component, I'll have to split them off into the X and Y components of momentum and look specifically at the X/horizontal component of momentum to use the conservation of momentum, if I'm not mistaken?

4.85 Cos(36^o) = 3.92m/s

p = mv
p = (0.200kg)(3.92m/s)
p = 1.2kg•m/s

Solve for momentum of that object.

p = mv
p = (0.200kg)(3.92m/s)
p = 0.784kg•m/s

Momentum of the other object (puck 2) is: 1.2kg•m/s - 0.784kg•m/s

= 0.416kg•m/s [Important: in the x/horizontal direction. need to solve for the angle'd direction]

0.416kg•m/s ÷ [cos(54^o)] =

0.707741472...kg•m/s !

I think with "their" answer, they rounded a bit too early.​

 

[tiny-tim]

Hi AceInfinity!

Momentum of the other object (puck 2) is: 1.2kg•m/s - 0.784kg•m/s

= 0.416kg•m/s [Important: in the x/horizontal direction. need to solve for the angle'd direction]

0.416kg•m/s / [cos(54^o)] =

0.707741472...kg•m/s !

yes that's fine

but there are quicker ways of doing it …

you could take components in the y direction or in the final direction of puck 2 …

(both are quicker because they reduce the number of terms)

try both of those ​

 

[PJC01]

Hello,

Thank you for bringing this problem to our attention. I am happy to help you understand how to solve this type of collision problem.

First, it is important to understand the concept of conservation of momentum. This principle states that the total momentum of a system is conserved in the absence of external forces. In other words, the total momentum before a collision is equal to the total momentum after the collision.

To solve this problem, we need to use the equations for conservation of momentum and conservation of kinetic energy. The equations are as follows:

Conservation of Momentum:
m1v1 + m2v2 = m1v1' + m2v2'

Conservation of Kinetic Energy:
1/2m1v1^2 + 1/2m2v2^2 = 1/2m1v1'^2 + 1/2m2v2'^2

Where:
m1 and m2 are the masses of the two objects
v1 and v2 are the velocities of the two objects before the collision
v1' and v2' are the velocities of the two objects after the collision

To solve the problem, you will need to use these equations and plug in the given values for mass and velocity. You will also need to use basic trigonometry to find the components of the velocities in the x and y directions.

I hope this explanation helps you understand how to solve this type of problem. If you have any further questions, please do not hesitate to ask. Good luck!