- #1
-Dragoon-
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Hey guys, it's me again!
Vectors have been really giving me a problem and turning me off from physics, but I hope I am getting the hang of it now.
Darryl drives his load of tomatoes 14.0 km [E], 6.0 km [N], 12.0 km [ N 15° E], and then 2.0 km [N 65° E]. This takes him 42 minutes. Calculate Darryl's distance and displacement.
a) Calculate Darryl's distance and displacement. Draw a diagram and show your work.
b) Calculate Darryl's average speed and average velocity (record your answer in m/s).
Magnitude * cosΘ = adjacent.
Magnitude * sinΘ = opposite.
C^2 = a^2 + b^2
What I first did was break the 12.0 [ N 15° E] into components and found by using sine and cosine law that it was 14.7 km [E] and 3.1 km [N]. Then I broke down 2.0 km [N 65° E] into components and using the same method above I broke it down to 1 km [E] and 1.7 km [N]. Now that all my vectors are either parallel or anti-parallel, I added or subtracted where appropriate. I ended up with a total value of 29.7 km [E] and 10.8 km [N]. I drew these and then drew the resultant vector and found it's magnitude by using pythagorean theorem. Then I found the angle by using the tangent function. I ended up with 31.6 km [E 20° N] as the total displacement. Is this correct? Did I do it right How would I calculate Darryl's distance?
And for part b, to find the average speed would just be: total distance/total time and for average velocity: total displacement/total time, correct?
Thanks in advance!
Vectors have been really giving me a problem and turning me off from physics, but I hope I am getting the hang of it now.
Homework Statement
Darryl drives his load of tomatoes 14.0 km [E], 6.0 km [N], 12.0 km [ N 15° E], and then 2.0 km [N 65° E]. This takes him 42 minutes. Calculate Darryl's distance and displacement.
a) Calculate Darryl's distance and displacement. Draw a diagram and show your work.
b) Calculate Darryl's average speed and average velocity (record your answer in m/s).
Homework Equations
Magnitude * cosΘ = adjacent.
Magnitude * sinΘ = opposite.
C^2 = a^2 + b^2
The Attempt at a Solution
What I first did was break the 12.0 [ N 15° E] into components and found by using sine and cosine law that it was 14.7 km [E] and 3.1 km [N]. Then I broke down 2.0 km [N 65° E] into components and using the same method above I broke it down to 1 km [E] and 1.7 km [N]. Now that all my vectors are either parallel or anti-parallel, I added or subtracted where appropriate. I ended up with a total value of 29.7 km [E] and 10.8 km [N]. I drew these and then drew the resultant vector and found it's magnitude by using pythagorean theorem. Then I found the angle by using the tangent function. I ended up with 31.6 km [E 20° N] as the total displacement. Is this correct? Did I do it right How would I calculate Darryl's distance?
And for part b, to find the average speed would just be: total distance/total time and for average velocity: total displacement/total time, correct?
Thanks in advance!