Solve the given problem that involves probability

In summary, the tree diagram breaks down the events and outcomes in a problem to help calculate the probabilities. In the given problem, we can use the tree diagram to find the probability of event B given that event A has not occurred, and then use that to solve for the probability of event B and event A occurring together. This results in a probability of 7/12 for event A given that event B has occurred.
  • #1
chwala
Gold Member
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Homework Statement
See attached
Relevant Equations
Probability
1677755033297.png


I would like to know how one can use the tree diagram...hence my post... otherwise, i was able to solve problem as follows,

a. ##P(A∩B)= \dfrac{3}{4} ×\dfrac{1}{5}=\dfrac{3}{20}##

b. ## P(B/A')=\dfrac{P(B)-\dfrac{3}{20}}{P(A')}##

##\dfrac{3}{7}=\dfrac{P(B)-\dfrac{3}{20}}{\dfrac{1}{4}}##

...

##P(B)=\dfrac{9}{35}##

c. ## P(A/B)=\dfrac{3}{20} ×\dfrac{35}{9}=\dfrac{7}{12}##
 

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  • #2
chwala said:
Homework Statement:: See attached
Relevant Equations:: Probability

View attachment 323090

I would like to know how one can use the tree diagram...hence my post... otherwise, i was able to solve problem as follows,

a. ##P(A∩B)= \dfrac{3}{4} ×\dfrac{1}{5}=\dfrac{3}{20}##

b. ## P(B/A')=\dfrac{P(B)-\dfrac{3}{20}}{P(A')}##

##\dfrac{3}{7}=\dfrac{P(B)-\dfrac{3}{20}}{\dfrac{1}{4}}##

...

##P(B)=\dfrac{9}{35}##

c. ## P(A/B)=\dfrac{3}{20} ×\dfrac{35}{9}=\dfrac{7}{12}##
See Conditional Probability Tree at https://www.cuemath.com/data/probability-tree-diagram/
 

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