- #1
lydiazmi
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Homework Statement
A neutron of mass m0 collides with an immobile atomic nucleus of carbon of mass m=12m0. Collision is considered central and elastic. how many times does the kinetic energy of neutron decreases during the collision.
Homework Equations
m=12m0
m0v0=mu-m0u
(m0v02)/2=(mu2)/2-(m0u02)/2
The Attempt at a Solution
v0= (mu-m0u0)/m0=
=(12m0u-m0u0)/m0=
=12u-u0
u=(v0+u0)/12
u2=(v02+2u0v0+u02)/144
v02=12u2-u02
u2=(v02+u02)/12
(v02+2u0v0+u02)/144=(v02+u02)/12
0=11u02-2u0v0+11v02)
I'm stuck here. I know tht I hv to find x=(u02)/(1v02) because (m0u02)/2=x(m0v02)/2
u02=xv02
(the answer is 1.4 times)