Solenoid Magnetic Field Help

In summary, the problem involves a 12m long 0.50mm diameter copper wire and a power supply with a 17A capacity. The first question asks for the magnetic field strength inside a 2.0cm diameter solenoid with the wire as closely spaced as possible. The second question asks for the magnetic field strength at the center of a single circular loop made from the wire. The equations used are B=u0nI and B=u0I/2r, where n is equal to 12 divided by the product of pi and the diameter of the solenoid or loop, and r is equal to half of the circumference of the solenoid or loop. There may be some uncertainty in the calculations,
  • #1
pat666
709
0

Homework Statement


You have 12m of 0.50mm diameter copper wire and a power supply capable of passing 17A through the wire.
a)What magnetic field strength would you obtain inside a 2.0cm diameter solenoid with the wire spaced as closely as possible?
b)What magnetic field strength would you obtain at the center of a single circular loop made from the wire?

Homework Equations


B=u0nI
B=u0I/2r

The Attempt at a Solution


a) n=pi*0.002=0.00628 or n=12/.00628=1909.86 not sure on this
B=4pi*E-7nI B=1.34*1076T or B=4.08*10-2
b) B=4piE-7=17/(2*.001)=1.1-3T


b is definitely wrong but I don't know why and I am completely unsure on a.
all help appreciated.
 
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  • #2
pat666 said:

Homework Statement


You have 12m of 0.50mm diameter copper wire and a power supply capable of passing 17A through the wire.
a)What magnetic field strength would you obtain inside a 2.0cm diameter solenoid with the wire spaced as closely as possible?
b)What magnetic field strength would you obtain at the center of a single circular loop made from the wire?

n = 12/π*0.0205

Radius of the single loop = R = 12/2π
 
  • #3
thanks for that, do you know what's wrong with a?
 

Related to Solenoid Magnetic Field Help

What is a solenoid?

A solenoid is a coil of wire wrapped around a cylindrical core. When an electric current is passed through the wire, it creates a magnetic field.

What is the purpose of a solenoid?

A solenoid is used to convert electrical energy into mechanical energy. It can create a strong magnetic field that can be used to move objects or control switches and valves.

How is the magnetic field strength of a solenoid determined?

The magnetic field strength of a solenoid is determined by the number of turns in the coil, the amount of current passing through the wire, and the material of the core. The closer the turns are to each other and the higher the current and permeability of the core, the stronger the magnetic field will be.

What factors affect the direction of the magnetic field in a solenoid?

The direction of the magnetic field in a solenoid is affected by the direction of the current flow and the direction of the coil. If the current flows in a clockwise direction, the magnetic field will be in a counter-clockwise direction and vice versa. The direction of the coil also determines the direction of the magnetic field lines.

How can a solenoid be used in everyday life?

Solenoids are used in various everyday devices such as doorbells, speakers, and electric motors. They are also used in security systems, lock mechanisms, and medical devices. Solenoids are also found in industrial applications such as in valves, pumps, and relays.

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