- #1
pjunky
- 22
- 0
Sin [Pi. (x-1)] / x-1; for x =1,2,3,...N
Sin [ Pi. (x-1) ] / (x-1) = ?
for x=1,2,3,4,...N
I think for Sin (x) / x =1
but, what about that.
Sin [ Pi. (x-1) ] / (x-1) = ?
for x=1,2,3,4,...N
I think for Sin (x) / x =1
but, what about that.