Significant figures -- wrong answer to Thermodynamics question?

In summary, the conversation discusses the precision of the calculation for heat using the first law, which involves a value for initial volume of 5 x 10^-3 m^3. The solution is 54500 J, but there is a debate on whether the final answer should be rounded to 1 significant figure, which would give 60000 J. The conversation also mentions the importance of considering the precision of the chart values for pressure and the conversion between atm and Pa when making calculations.
  • #1
ChiralSuperfields
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Homework Statement
I am confused why the answer to the problem below has more significant figures than it should.
Relevant Equations
##\Delta E_{int} = Q - W##
For this problem,
1680317487199.png

The solution is, ## Q = 54500 J ## , however, since the calculation for heat uses the first law which involves ##5 \times 10^{-3) m^3 ## value for the initial volume, should the finial answer not be to 1 sig fig as well? This would give ## 60000 J ##.

Many thanks!
 

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  • #2
Whether it is ##5\cdot 10^{-3}##, ##5.0\cdot 10^{-3}##, ##5.00\cdot 10^{-3}## etc. depends on how precisely you think you can read it off the chart. Similarly the other chart readings. The more limiting precision would be the 30kJ.
 
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  • #3
haruspex said:
Whether it is ##5\cdot 10^{-3}##, ##5.0\cdot 10^{-3}##, ##5.00\cdot 10^{-3}## etc. depends on how precisely you think you can read it off the chart. Similarly the other chart readings. The more limiting precision would be the 30kJ.
Thank you for your reply @haruspex!

True you make a very valid point! I had not considered that the chart values could have more sig figs that they point.
 
  • #4
I think they expect you to observe that at 5 l, the pressure is 50 atm and at 12 l, the pressure is 20 atm, (exactly). They apparently took the conversion between atm and Pa to be 1.00000 rather than 101325.
 
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  • #5
Chestermiller said:
I think they expect you to observe that at 5 l, the pressure is 50 atm and at 12 l, the pressure is 20 atm, (exactly). They apparently took the conversion between atm and Pa to be 1.00000 rather than 101325.
Thank you for reply @Chestermiller !
 

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