Showing that the mean of one number and its absolute val...

In summary: No. You were asked to prove that 0 \leq \frac{x+|x|}{2} \leq |x| Note that this is "##\geq 0##", not "##\leq 0##", but, of course, they are the same thing when you actually have "##= 0##".In summary, the task is to prove that the mean of one number and its absolute value is greater than or equal to 0 and less than or equal to the absolute value of the number. This can be done using the method of case, where the first case is x≥0 and the second case is x<0. By substituting |x|=x
  • #1
astrololo
200
3

Homework Statement


I must prove that the mean of one number and its absolute value is superior or equal to 0 but inferior or equal to the absolute value of the number

Homework Equations


I must prove this by the method of case.

The Attempt at a Solution



I know that the first case is : x>=0 and the second x<0

But after that, I have no idea on how to do this...
 
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  • #2
astrololo said:

Homework Statement


I must prove that the mean of one number and its absolute value is superior or equal to 0 but inferior or equal to the absolute value of the number

Homework Equations


I must prove this by the method of case.

The Attempt at a Solution



I know that the first case is : x>=0 and the second x<0

But after that, I have no idea on how to do this...
What are the cases you refer to ?
 
  • #3
SammyS said:
What are the cases you refer to ?
You mean you don't understand what the proof by case is ? I mean that to arrive to my result, I must begin x>=0 and the second case is x<0. After, I imagine there is some sort of addition that I Must do to obtain my final result.
 
  • #4
SammyS said:
What are the cases you refer to ?
Are you still here ? I think that I must do this : x<0 then absolute(x)=-x

and x>=0 then absolute(x)=x
 
  • #5
astrololo said:
You mean you don't understand what the proof by case is ? I mean that to arrive to my result, I must begin x>=0 and the second case is x<0. After, I imagine there is some sort of addition that I Must do to obtain my final result.
I misread your post.

Case 1: x ≥ 0
If x ≥ 0, what is |x| ?
 
  • #6
SammyS said:
I misread your post.

Case 1: x ≥ 0
If x ≥ 0, what is |x| ?
Then this means |x|=x

And if x<0 then this means |x|=-x
 
  • #7
astrololo said:
Are you still here ? I think that I must do this : x<0 then absolute(x)=-x

and x>=0 then absolute(x)=x
Yes. That's the way to start each part.
 
  • #8
SammyS said:
Yes. That's the way to start each part.
Yeah, I was able to understand this. Here is what I did after :

|x|=x add x on each side

|x|+x=2x

divide by 2

(|x|+x)/2=x

Case 2 :

|x|=-x

|x|+x=x-x

|x|+x=0

Multiply by 1/2 by each side.

(|x|+x)/2=0

Is this correct ?
 
  • #9
astrololo said:
Yeah, I was able to understand this. Here is what I did after :

|x|=x add x on each side

|x|+x=2x

divide by 2

(|x|+x)/2=x

Case 2 :

|x|=-x

|x|+x=x-x

|x|+x=0

Multiply by 1/2 by each side.

(|x|+x)/2=0

Is this correct ?
Yes.
 
  • #10
SammyS said:
Yes.
Ok, I guess that I must use my x<=0 inequality and replace the x.

(|x|+x)/2<=0
 
  • #11
astrololo said:
Ok, I guess that I must use my x<=0 inequality and replace the x.

(|x|+x)/2<=0

No. You were asked to prove that
[tex] 0 \leq \frac{x+|x|}{2} \leq |x| [/tex]
Note that this is "##\geq 0##", not "##\leq 0##", but, of course, they are the same thing when you actually have "##= 0##".
 

Related to Showing that the mean of one number and its absolute val...

1. What is the formula for finding the mean of a number and its absolute value?

The formula for finding the mean of a number and its absolute value is (x + |x|) / 2, where x is the given number.

2. How do you interpret the mean of a number and its absolute value?

The mean of a number and its absolute value represents the average distance of the number from zero. It takes into account both positive and negative values.

3. Can the mean of a number and its absolute value ever be negative?

No, the mean of a number and its absolute value will always be a positive value. This is because the absolute value of a number is always positive, and when added to the number, it increases the overall value.

4. How does the mean of a number and its absolute value change when the number is negative?

The mean of a number and its absolute value will remain the same regardless of whether the number is positive or negative. This is because when a negative number is added to its absolute value, the result is always positive.

5. What other measures of central tendency can be used for a number and its absolute value?

In addition to the mean, the median and mode can also be used as measures of central tendency for a number and its absolute value. However, the mean is the most commonly used measure in this case.

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