Sharp Cut off in bremsstralungh

[warrior_1]

Hi with respect to the bremsstralung and the Xray emission, i have a graph of the xray emmision and at the end of the bremsstrahlung, at roughly 35 KeV,there is a sharp cut off.

Is the reason for this because that 35KeV is the maximum energy of the incident
electrons, and hence no photon can be emitted with larger energy than
this, as it is only possible to produce a photon of this energy if the
electron is completely brought to a stop as it passes through the
nuclues?

 

[Dadface]

Hi with respect to the bremsstralung and the Xray emission, i have a graph of the xray emmision and at the end of the bremsstrahlung, at roughly 35 KeV,there is a sharp cut off.

Is the reason for this because that 35KeV is the maximum energy of the incident
electrons, and hence no photon can be emitted with larger energy than
this, as it is only possible to produce a photon of this energy if the
electron is completely brought to a stop as it passes through the
nuclues?

Correct.Some electrons lose all of their kinetic energy on a single impact.If you use a different accelerating voltage the cut off will change accordingly.

 

[kerimek]

Yes, you are correct. The sharp cut off at 35 KeV is due to the maximum energy of the incident electrons. This is known as the "energy cutoff" and it is a fundamental principle of bremsstrahlung radiation. As an electron passes through the nucleus, it experiences a deceleration due to the Coulomb force. This deceleration results in the emission of photons, with the maximum energy being equal to the initial kinetic energy of the electron. Once the electron reaches 35 KeV, it no longer has enough energy to produce X-rays and thus, the sharp cut off is observed in the X-ray emission spectrum. This phenomenon is important in understanding the production of X-rays and is utilized in various applications, such as medical imaging and industrial inspections.