- #1
nateHI
- 146
- 4
The Schrodinger equation for the complex conjugate of a ket vector is:
d/dt<sai(t)| = -(<sai(t)|H)/(i*hcross)
How do you derive the above equation from the normal form of the schrodinger equation? I'm mostly confused by where the negative sign is coming from.
Thanks
d/dt<sai(t)| = -(<sai(t)|H)/(i*hcross)
How do you derive the above equation from the normal form of the schrodinger equation? I'm mostly confused by where the negative sign is coming from.
Thanks