Scaled applied forces for an elastic rod

In summary, the concept of a scaled applied force for an elastic rod involves applying a force to the rod in a way that results in a proportional deformation. This is calculated by multiplying the original force by a scaling factor determined by the material's Young's modulus and cross-sectional area. This concept can be applied to all types of elastic materials and allows for more accurate and controlled experiments. However, a limitation is that it assumes linear behavior, which may not be the case for some materials.
  • #1
onie mti
51
0
am having difficulty in understanding this problem and frankly I don't know how to approach it, please assist on how to solve itThey say that an elastic rod is modeled as the half time[0,infinity). initially it is at rest. at the end point x=o, a force f(t) is applied then they give me the scaled system for the motion

ut(x,t)+ Fx(x,t)=0
Fx(x,t)+ux(x,t)=0
F(0,t)=f(t);
x>0 t>0

the question is: to solve the problem if the scaled applied force is of the form f(t)=sint
 
Physics news on Phys.org
  • #2
onie mti said:
am having difficulty in understanding this problem and frankly I don't know how to approach it, please assist on how to solve itThey say that an elastic rod is modeled as the half time[0,infinity). initially it is at rest. at the end point x=o, a force f(t) is applied then they give me the scaled system for the motion

ut(x,t)+ Fx(x,t)=0
Fx(x,t)+ux(x,t)=0
F(0,t)=f(t);
x>0 t>0

the question is: to solve the problem if the scaled applied force is of the form f(t)=sint

Is pratically the same problem You met in...

http://mathhelpboards.com/differential-equations-17/scaled-transport-equation-10626.html

Because $\displaystyle u_{x} + F_{x} = u_{t} + F_{x} = 0$ is also...

$\displaystyle u_{x} - u_{t} = 0\ (1)$

... and the solution of (1) is...

$\displaystyle u(x,t) = f(x + t)\ (2)$

... where $f(*,*) \in C^{1}$. Taking into account the boundary conditions is...

$\displaystyle u(x,t) = \cos (x + t)\ (3)$

Kind regards

$\chi$ $\sigma$
 

Related to Scaled applied forces for an elastic rod

1. What is the concept of a "scaled applied force" for an elastic rod?

The concept of a scaled applied force for an elastic rod refers to the process of applying a force to an elastic rod in such a way that the resulting deformation is proportional to the applied force. This allows for the rod to behave in a predictable and consistent manner under different levels of applied force.

2. How is a scaled applied force calculated for an elastic rod?

A scaled applied force is calculated by multiplying the original applied force by a scaling factor. This scaling factor is determined by the Young's modulus of the material and the cross-sectional area of the rod.

3. Can a scaled applied force be used for any type of elastic rod?

Yes, a scaled applied force can be used for any type of elastic rod as long as the material properties and dimensions of the rod are known. This concept is applicable to all types of elastic materials, including metals, plastics, and composites.

4. What is the significance of using a scaled applied force for an elastic rod?

The use of a scaled applied force for an elastic rod allows for a more accurate and controlled experiment, as the resulting deformation of the rod is directly proportional to the applied force. This makes it easier to compare and analyze data, and also allows for the prediction of how the rod will behave under different levels of force.

5. Are there any limitations to using a scaled applied force for an elastic rod?

One limitation of using a scaled applied force for an elastic rod is that it assumes the rod behaves in a linear manner, meaning the deformation is directly proportional to the applied force. In reality, some materials may exhibit non-linear behavior, which can affect the accuracy of the results.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Differential Equations
Replies
2
Views
2K
  • Classical Physics
Replies
17
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
865
  • Introductory Physics Homework Help
Replies
6
Views
290
  • Calculus and Beyond Homework Help
Replies
7
Views
406
Replies
2
Views
1K
  • Differential Equations
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Advanced Physics Homework Help
Replies
3
Views
1K
Back
Top