Relativistic centripetal force question

In summary, the relativistic centripetal force on a mass moving on a circular path is the centripetal acceleration, v*v/r, times rest mass times gamma squared.
  • #1
teve
19
0
The last post in the thread https://www.physicsforums.com/showthread.php?t=466305 seems to say that the relativistic force on a mass moving on a circular path is the centripetal acceleration, v*v/r, times rest mass times gamma squared.

But the articles http://en.wikipedia.org/wiki/Force#Special_relativity and http://en.wikipedia.org/wiki/Special_theory_of_relativity#Force seem to suggest the force is the centripetal acceleration time rest mass times just gamma.

What am I missing? Are the situations different? If so, how?
 
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  • #3
So then what is the magnitude of the (relativistic) centripetal force on a particle with rest mass m traveling at velocity v in a circle of radius r as observed from a frame at rest with the center of the circle? Is it (mvv/r) times gamma, or gamma squared? It is still not clear to me. It seems this should be a simple question and should have one answer.
 
  • #4
Gamma to the first power. The spacelike part of the force four-vector simply isn't the force.
 
  • #5
OK. Then in the LHC with gamma=7500, r=4300m (C=27000m), 2808 bunches of 1.15e11 protons each (proton m=1.67e-27kg), the LHC dipole magnets exert (on the average) a radial inward force per meter of very nearly (7500*(1.67e-27kg*2808*1.15e11)(c^2)/4300m)/27000m=3.131 N/m. 6.262 N/m for the two beams. Is this a correct application of the formula?
 
  • #6
teve said:
What am I missing? Are the situations different? If so, how?
The magnitude of the four-force (gamma squared) is the force felt by the accelerating particle, it is a relativistic invariant. The magnitude of the force three-vector (gamma) is the force measured in the "lab" frame, it is frame variant.

teve said:
It seems this should be a simple question and should have one answer.
Things rarely have a single answer in relativity unless you pay very careful attention to the details.
 
  • #7
DaleSpam said:
The magnitude of the four-force (gamma squared) is the force felt by the accelerating particle, it is a relativistic invariant. The magnitude of the force three-vector (gamma) is the force measured in the "lab" frame, it is frame variant.

Things rarely have a single answer in relativity unless you pay very careful attention to the details.


Thanks for that simple explanation. Now I can check that off on my list of things to figure out.
 

Related to Relativistic centripetal force question

1. What is the formula for calculating relativistic centripetal force?

The formula for calculating relativistic centripetal force is F = (mv^2)/r, where F is the force, m is the mass of the object, v is the velocity, and r is the radius of the circular motion.

2. How does relativistic centripetal force differ from classical centripetal force?

Relativistic centripetal force takes into account the effects of special relativity, such as time dilation and length contraction, while classical centripetal force only considers the velocity and mass of the object.

3. Can relativistic centripetal force be applied to objects moving at any speed?

Yes, relativistic centripetal force can be applied to objects moving at any speed, as long as the speed is significant enough to have relativistic effects.

4. How does relativity affect the magnitude of centripetal force?

Relativity can affect the magnitude of centripetal force by causing the mass and velocity of the object to change, which in turn affects the force required to maintain circular motion.

5. What are some real-life examples of relativistic centripetal force?

Some real-life examples of relativistic centripetal force include the rotation of planets around the sun, the motion of particles in particle accelerators, and the rotation of galaxies.

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