# Ratio Word Problem

#### kuheli

##### New member
hi ,

this is one simple math but i am not getting the answer.

the work done by (x-3) men in (2x+1) days and the work done by (2x+1)men in (x+4) days are in the ratio of 3:10.find the value of 'x'.

#### Amer

##### Active member
Re: ratio

hi ,

this is one simple math but i am not getting the answer.

the work done by (x-3) men in (2x+1) days and the work done by (2x+1)men in (x+4) days are in the ratio of 3:10.find the value of 'x'.
suppose the amount of work done by a man per day is y

(x-3) men done y(x-3) per day, and y(x-3)(2x+1) per (2x+1) days
Total work done by the first group is y(x-1)(2x+1)
In same manner the other group will do y(2x+1)(x+4)
we have to solve this equation
$$\frac{y(2x+1)(x-1)}{y(2x+1)(x+4)} = \frac{3}{10}$$

#### kuheli

##### New member
Re: ratio

suppose the amount of work done by a man per day is y

(x-3) men done y(x-3) per day, and y(x-3)(2x+1) per (2x+1) days
Total work done by the first group is y(x-1)(2x+1)
In same manner the other group will do y(2x+1)(x+4)
we have to solve this equation
$$\frac{y(2x+1)(x-1)}{y(2x+1)(x+4)} = \frac{3}{10}$$
do you think the numerator of the fraction is
y(2x+1)(x-1) or y(2x+1)(x-3) ???