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- #1
Ratio Word Problem
- Thread starter kuheli
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Re: ratio
(x-3) men done y(x-3) per day, and y(x-3)(2x+1) per (2x+1) days
Total work done by the first group is y(x-1)(2x+1)
In same manner the other group will do y(2x+1)(x+4)
we have to solve this equation
[tex]\frac{y(2x+1)(x-1)}{y(2x+1)(x+4)} = \frac{3}{10}[/tex]
suppose the amount of work done by a man per day is yhi ,
this is one simple math but i am not getting the answer.
the work done by (x-3) men in (2x+1) days and the work done by (2x+1)men in (x+4) days are in the ratio of 3:10.find the value of 'x'.
(x-3) men done y(x-3) per day, and y(x-3)(2x+1) per (2x+1) days
Total work done by the first group is y(x-1)(2x+1)
In same manner the other group will do y(2x+1)(x+4)
we have to solve this equation
[tex]\frac{y(2x+1)(x-1)}{y(2x+1)(x+4)} = \frac{3}{10}[/tex]
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- #3
Re: ratio
y(2x+1)(x-1) or y(2x+1)(x-3) ???
do you think the numerator of the fraction issuppose the amount of work done by a man per day is y
(x-3) men done y(x-3) per day, and y(x-3)(2x+1) per (2x+1) days
Total work done by the first group is y(x-1)(2x+1)
In same manner the other group will do y(2x+1)(x+4)
we have to solve this equation
[tex]\frac{y(2x+1)(x-1)}{y(2x+1)(x+4)} = \frac{3}{10}[/tex]
y(2x+1)(x-1) or y(2x+1)(x-3) ???