- #1
Hakkinen
- 42
- 0
I just have a question about the problem for when the eigenvalue = 0
for [itex] y_{xx}=-\lambda y [/itex] with BC [itex]y(0)=0 , y'(0)=y'(1) [/itex]
y for lamda = 0 is ax+b
so from BC:
y(0)=b=0
and a=a
What is the conclusion to make from this? lamda = 0 and the eigenfunction is constant?
Homework Statement
for [itex] y_{xx}=-\lambda y [/itex] with BC [itex]y(0)=0 , y'(0)=y'(1) [/itex]
Homework Equations
The Attempt at a Solution
y for lamda = 0 is ax+b
so from BC:
y(0)=b=0
and a=a
What is the conclusion to make from this? lamda = 0 and the eigenfunction is constant?