Questions involving implicit differentiation,

In summary, this conversation involves finding the derivatives of several equations, including using the product rule and quadratic formula. The expert summarizer suggests differentiating each equation separately and shows the steps for finding the derivative of each term. For the last question, the expert suggests using the distance formula and differentiating to find the rate of change.
  • #1
slain4ever
63
0

Homework Statement



Q1. using implicit diff to find dy/dx when x^2 y + 6xy^2 = 5x-2
Q2. Find max and min values of y= x^3 -3x^2 -6x + 7 on the interval -3<=x<=5
Q3.Find the exact values of the x coordinate of the points of inflexion on the graph of y = 2x^4 +3x^2 +x +5

Q4. a red car is traveling east from a point at 60kph while a blue car is traveling north away from the point at 60kph. if the red car is 3km from the point and the blue car is 4km from the point at what rate is the distance between the cars changing?

The Attempt at a Solution



Q1. ? no clue, differentiate each part seperately or something like that

Q2. differentiate the equation substitute this into the quadratic formula and get two values (62.76 and 5.24) but according to this there is nothing that fits into the interval so i must have done it wrong.

Q3. Derive it twice, substitute into quadratic formula and find two value for x.. Then do something else which I am not sure of.

Q4. something to do with s^2 = x^2 + y^2 and deriving for ds/dt but I am not sure if this is correct or even how to do it.

Any help would be greatly appreciated.
 
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  • #2
slain4ever said:

Homework Statement



Q1. using implicit diff to find dy/dx when x^2 y + 6xy^2 = 5x-2
Q2. Find max and min values of y= x^3 -3x^2 -6x + 7 on the interval -3<=x<=5
Q3.Find the exact values of the x coordinate of the points of inflexion on the graph of y = 2x^4 +3x^2 +x +5

Q4. a red car is traveling east from a point at 60kph while a blue car is traveling north away from the point at 60kph. if the red car is 3km from the point and the blue car is 4km from the point at what rate is the distance between the cars changing?

The Attempt at a Solution



Q1. ? no clue, differentiate each part seperately or something like that
Sounds good. What do you get when you do that?
Q2. differentiate the equation substitute this into the quadratic formula and get two values (62.76 and 5.24) but according to this there is nothing that fits into the interval so i must have done it wrong.
Show your work. We can't really help if all you tell us is you got the wrong answer. Your approach is right. You just messed up the execution of it.
Q3. [STRIKE]Derive[/STRIKE] Differentiate it twice, substitute into quadratic formula and find two value for x.. Then do something else which I am not sure of.
What do you get for x when you do that? You don't have to do anything more. The points of inflection are where y''=0. The problem is asking you to find the values of x where that's true.
Q4. something to do with s^2 = x^2 + y^2 and [STRIKE]deriving[/STRIKE] differentiating for ds/dt but I am not sure if this is correct or even how to do it.

Any help would be greatly appreciated.
Yes, this is a good way to start. If x(t) is the position of one car on the x-axis and y(t) the other on the y-axis, s(t) is the distance between them, and ds/dt will be the rate of change of this distance, which is what you're being asked to find.
 
  • #3
slain4ever said:

Homework Statement



Q1. using implicit diff to find dy/dx when x^2 y + 6xy^2 = 5x-2


Let's start with this one. Yes you need to differentiate each one separately.

for 'x2y' use the product rule.


remember that when you differentiate y wrt x, you will get dy/dx

so if you differentiate y2 wrt x you will get 2y(dy/dx)
 

Related to Questions involving implicit differentiation,

1. What is implicit differentiation?

Implicit differentiation is a mathematical technique used to find the derivative of a function that is given implicitly, or in terms of both x and y. It allows us to find the slope of a curve at a given point without explicitly solving for y.

2. How is implicit differentiation different from explicit differentiation?

Explicit differentiation involves finding the derivative of a function that is given explicitly in terms of x. This means that y is already isolated on one side of the equation. Implicit differentiation, on the other hand, involves differentiating a function that is given implicitly in terms of both x and y.

3. When is implicit differentiation useful?

Implicit differentiation is useful when it is difficult or impossible to solve for y explicitly. It is commonly used in physics and engineering problems, as well as in finding the equations of tangent lines to curves.

4. What are the steps for implicit differentiation?

The steps for implicit differentiation are as follows:

  1. Differentiate both sides of the equation with respect to x.
  2. Use the chain rule for any terms that involve y.
  3. Solve for dy/dx.

5. Can implicit differentiation be used for higher order derivatives?

Yes, implicit differentiation can be used to find higher order derivatives. It follows the same steps as finding the first derivative, but the chain rule may need to be applied multiple times.

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