QR Decomposition of Matrix: Solve for Answers

In summary, the matrix is supposed to be next to the previous one but I can't figure out how to do that. I'm also not worried about the R part right now.
  • #1
g.lemaitre
267
2

Homework Statement


Decompose the following matrix using QR decomposition
\begin{bmatrix}
4 & 1 \\
3 & -1
\end{bmatrix}
the answer is
\begin{bmatrix}
.8 & .6 \\
.6 & .8
\end{bmatrix}
The following matrix is supposed to be next to the previous but I can't figure out how to do that. Any help in that area would be appreciated.
\begin{bmatrix}
5 & .2 \\
0 & 1.4
\end{bmatrix}

Homework Equations


[tex] c_2 = (v_2 * u_1)q_1 + \parallel w_2 \parallel q_2 [/tex]

The Attempt at a Solution


I was able to get the first part of the answer
\begin{bmatrix}
.8 & \\
.6 &
\end{bmatrix}
It's the second part
\begin{bmatrix}
.6 & \\
-.8 &
\end{bmatrix}
that I'm having trouble with. I'm also not worried about the R part right now.
Ok, let's plug the numbers into this equation:
[tex] c_2 = (v_2 * u_1)q_1 + \parallel w_2 \parallel q_2 [/tex]
[tex]v_2 * u_1 = .2 [/tex]
[tex] c_2 = \begin{bmatrix}
1 & \\
-1 &
\end{bmatrix}
[/tex]
[tex] \parallel w_2 \parallel = -49/25 [/tex]
Therefore,
[tex] \begin{bmatrix}
1 & \\
-1 &
\end{bmatrix} = .2 \begin{bmatrix}
.8 & \\
.6 &
\end{bmatrix} - 49/25q_2 [/tex]
step two
[tex] \begin{bmatrix}
1 & \\
-1 &
\end{bmatrix} = \begin{bmatrix}
4/25 & \\
3/25 &
\end{bmatrix} - 49/25q_2 [/tex]
step three
[tex]
\begin{bmatrix}
(25-4)/25 & \\
(-25-3)/25 &
\end{bmatrix} = 49/25q_2[/tex]
step four
[tex]
\begin{bmatrix}
21/49 & \\
-28/49 &
\end{bmatrix} = q_2[/tex]
The answer is supposed to be
[tex]
\begin{bmatrix}
.6 & \\
-.8 &
\end{bmatrix} = q_2
[/tex]
So I made an error somewhere.
 
Last edited:
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  • #2
It's tough to follow because you haven't defined every symbol, but ##q_2## should have unit norm. If you properly normalize your result, you'll find that it agrees with the solution.
 
  • #3
fzero said:
It's tough to follow because you haven't defined every symbol, but ##q_2## should have unit norm. If you properly normalize your result, you'll find that it agrees with the solution.

what do you mean by properly normalize.
 
  • #4
To normalize a vector q is to find q / ||q||. Bascially, it means to scale the vector so that it lies on the unit sphere.
 
  • #5
amazing it worked! i was skeptical that it would but it did!
 

Related to QR Decomposition of Matrix: Solve for Answers

What is QR Decomposition of Matrix?

QR Decomposition of Matrix is a mathematical method used to decompose a matrix into an orthogonal matrix and an upper triangular matrix. It is often used in solving systems of linear equations and matrix inversion.

Why is QR Decomposition of Matrix important?

QR Decomposition of Matrix is important because it allows for efficient and accurate solutions to systems of linear equations and matrix inversion. It also helps in reducing computational complexity and improving numerical stability.

How is QR Decomposition of Matrix calculated?

QR Decomposition of Matrix is calculated using the Gram-Schmidt process, which involves orthogonalizing the columns of the matrix and then finding an upper triangular matrix using the orthogonalized columns.

What are the applications of QR Decomposition of Matrix?

QR Decomposition of Matrix has various applications in fields such as engineering, physics, and statistics. It is used in solving linear regression problems, calculating eigenvalues and eigenvectors, and in signal processing.

What are the advantages of QR Decomposition of Matrix over other methods?

QR Decomposition of Matrix is advantageous because it is numerically stable and produces accurate solutions. It also has a lower computational complexity compared to other methods such as LU decomposition.

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