- #1
physicsgivesmeCs
- 1
- 0
How fast is the pumpkin moving at the bottom if theta = 30 degrees, L = 5 m, g = 9.8 m/s^2, m = 10 kg.
L is the length of the string holding the pumpkin. M is the mass of the pumpkin. It's like a pendulum, the pumpkin is positioned at 30 degrees from the vertical and let go. Assume no air resistance/friction.
L is the length of the string holding the pumpkin. M is the mass of the pumpkin. It's like a pendulum, the pumpkin is positioned at 30 degrees from the vertical and let go. Assume no air resistance/friction.
Last edited: