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iomtt6076
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Homework Statement
Prove: Let [tex] A \in \mathrm{M}_{n \times n}(\mathbb{F}) [/tex] and let [tex] \gamma [/tex] be an ordered basis for [tex] \mathbb{F}^n [/tex]. Then [tex] [\boldmath{L}_A]_{\gamma} = Q^{-1}AQ [/tex], where Q is the nxn matrix whose jth column is the jth vector of [tex] \gamma [/tex].
Homework Equations
[tex] \boldmath{L}_A [/tex] denotes the left-multiplication transformation.
The Attempt at a Solution
Let [tex] \beta [/tex] be the standard ordered basis for [tex] \mathbb{F}^n [/tex] and C the change of coordinate matrix from [tex] \beta [/tex]-coordinates to [tex] \gamma [/tex]-coordinates. Then [tex] [\boldmath{L}_A]_{\beta} = A [/tex] and we have [tex] [\boldmath{L}_A]_{\gamma} = C^{-1}AC [/tex]. Where I'm stuck is showing that the jth column of C is the jth vector of [tex] \gamma [/tex]. Any hints would be appreciated.