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Homework Statement
T is a compact metric space with metric d. f:T->T is continuous and for every x in T f(x)=x. Need to show g:T->R is continous, g(x)=d(f(x),x).
Homework Equations
The Attempt at a Solution
f is continuous for all a in T if given any epsilon>0 there is a delta>0 st d(x,a)<delta implies d(f(x),f(a))<epsilon. Need to show there is a delta st d(x,a)< delta implies |g(x)-g(a)|<epsilon.
by a previous problem i did... |g(x)-g(a)|=|d(f(x),x)-d(f(a),a)|<= d(f(x),f(a))+d(x,a)<d(f(x),f(a)) + delta. This is where I got stuck. from the assumption that f is continuous we got from there that d(f(x),f(a))<epsilon. but if i say that then i would have...|g(x)-g(a)|<epsilon + delta and inorder for |g(x)-g(a)|to be <epsilon we would have to choose delta to be 0 which it can't be because it has to be greater than 0. any suggestions on what i should do?