Properties of Limits:Lim 2^(1/n) = 2^0 = 1

In summary, the property being discussed is not a property of limits, but rather a property of the function f(x)=2^x, which is continuous at x=0. This means that the limit of 2^x can be evaluated as 2 ^ lim x. Additionally, there is a "law of limits" that states if the limit of a function f(x) is L and the limit of a sequence x_n is a, then the limit of f(x_n) is also L.
  • #1
tarheelborn
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Homework Statement



What property of limits says that lim 2^(1/n) = 2^lim (1/n) = 2^0 = 1? Thanks.

Homework Equations





The Attempt at a Solution

 
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  • #2
It's not a property of limits. It's a property of the function f(x)=2^x. f(x) is continuous at x=0.
 
  • #3
I don't follow that. Because 2^x is continuous at x = 0, this means that lim 2^x = 2 ^ lim x?
 
  • #4
f(x) is continuous at x=a means lim x->a f(x)=f(a). That's the definition of continuity. Apply it to f(x)=2^x and a=0.
 
  • #5
Oh, duh... Thank you so much.
 
  • #6
But there is a "law of limits" involved:

If [itex]\lim_{x\to a} f(x)= L[/itex] and [itex]\lim_{n\to\infty} x_n= a[/itex] then [itex]\lim_{n\to\infty} f(x_n)= L[/itex].
 

Related to Properties of Limits:Lim 2^(1/n) = 2^0 = 1

What is the meaning of "Lim 2^(1/n) = 2^0 = 1"?

The notation "Lim" stands for limit, which represents the value that a function approaches as its input approaches a given value. In this case, as the exponent (1/n) approaches 0, the value of the function 2^(1/n) approaches 1.

What is the significance of the exponent (1/n) in the function 2^(1/n)?

The exponent (1/n) represents a variable power, where n is a positive integer. This means that as n increases, the value of the function decreases. In the limit, as n approaches infinity, the value of the function approaches 1.

How does the value of the limit change if the base of the function is changed?

The value of the limit will change depending on the base of the function. For example, if the base is changed to 3, the limit will become 3^0 = 1. This is because the limit only depends on the behavior of the function near the given value, not on the value itself.

Can the limit of 2^(1/n) be approximated using numerical methods?

Yes, the limit can be approximated using numerical methods such as graphing or using a calculator. As n approaches 0, the value of the function will become increasingly closer to 1.

Why is the limit of 2^(1/n) equal to 1?

The limit of 2^(1/n) is equal to 1 because as n approaches 0, the exponent approaches 0. Any number raised to the power of 0 is equal to 1, so the limit of the function is 1.

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