- #1
Arty7
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The question is in the attachment.
a) for the height i got 1.25m which you get by using displacement and acceleration. (t=20/40=0.5sec)
b) a=v/t, 10*0.5=5m/s
c) At initial point:
mgh= 0.040*10*1.25=0.5J
1/2mv^2=1/2*0.040*40^2=32J
Hits Ground:
mgh=0.040*10*0=0J
1/2mv^2=1/2*0.040*(20 or 40)^2 ? The answer is 32.5J I am not sure what happens here and how to get that. Do you add the energys from initial point together?
a) for the height i got 1.25m which you get by using displacement and acceleration. (t=20/40=0.5sec)
b) a=v/t, 10*0.5=5m/s
c) At initial point:
mgh= 0.040*10*1.25=0.5J
1/2mv^2=1/2*0.040*40^2=32J
Hits Ground:
mgh=0.040*10*0=0J
1/2mv^2=1/2*0.040*(20 or 40)^2 ? The answer is 32.5J I am not sure what happens here and how to get that. Do you add the energys from initial point together?
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