Please help Need solution to Second Order nonlinear DE

In summary, you are trying to solve for the height of a rocket as a function of time. You have found that the equation is first order and that the only terms are the derivatives of y. You are trying to find a first order equation for the v term, assuming that it is a function of y'.
  • #1
ELEN_guy
8
0
Does anyone know how to solve the following Non-linear, second order, differential equation?

A*y" + B*(y')^2 = F(t) + C

where A, B, & C are constants

**please note, in case the above notation isn't clear, the y' term is squared which is what makes it non-linear. Also, F(t) is time dependent.

I tried using the following substitution:

y' = u ..giving rise to.. y" = u'

this yields the following DE:

A*u' + B*u^2 = F(t) + C

which is now at least a first-order DE but I still can't solve it.

does anyone knows how to solve either one of these DE's please let me know.

Thanks^googol
 
Physics news on Phys.org
  • #2
Is your differeation variable of your unknown function also t?

y = y(t) and y' = dy/dt


If not than F(t) + C can be called some new constant.
 
  • #3
Are A, B, and C necessarily independent?
 
  • #4
The differentiation variable is NOT t, its just some other variable..lets say x:

y = y(x), y' = dy/dx..and so on

yeah that makes sense.. F(t) + C = K

A, B, and C are constants which are not zero, one, or equal to each other.
 
  • #5
A*y" + B*(y')^2 = K

I think it might be a sum of two different powers of x. Try a power series.


inf
y = Sum {Dn x^n }
n=0

I'll try on paper.

You know how people get thoes nice emeded forumlas that look like mathmatica? Is that imbeded in this forum somewhere?
 
  • #6
Thanks! not sure how to use power series to solve DE's...never covered that topic when I took my diff eq course. don't know how to imbed those formulas either..
 
  • #7
What does this DE physically represent or is this just a math exercise?
 
  • #8
yes, it represents the equation of motion of an inertial system with a drag force and an external force which is NOT time-related. Namely, its an idealized model of the Apollo reentry.

The differentiation variable is, in fact, time dependent while the F(x) + C term is not...I just wrote the reverse since it was easier to type in using "primes" instead of "dots" without the imbedded notation.

I appreciate your help!
 
  • #9
Well, I'm on a library computer and I just discovered they have Maple (which I don't know well). Without knowing the simplify function, this is what maple spit out.

y(x) = -(1/2)*(2*sqrt(k)*sqrt(b)*x+ln(4*k/(b*(_C1*exp(2*sqrt(k)*sqrt(b)*x/a)-_C2)^2))*a)/b

I'm trying to find the FullSImplify[] function. C1 and C2 are the two constants required for a 2nd degree DE. That expression's not much use unless you have something to clean it up on your side.
 
  • #10
Once again, thanks a lot for taking the time to help! I totally forgot about Maple..I'm going to see if anyone on my team knows it well. At this point I'm about ready to take that expression and make up some constants to fit the data.
 
  • #11
Apollo re-entry. Cool problem.

A*y" + B*(y')^2 = F(x) + C

You say the primes are actually time derivitives. I assume the y'' was the acceleration term and the (y')^2 term is the drag force, making the actual function the height of the craft as a function of time?

Wouldn't drag force also be a function of the density of the atmosphere, thus making the drag term some function of your height y?

What are the other terms?
 
  • #12
Since only the derivatives of y appear in that equation, the obvious thing to do is to let v= y' and have Av'+ Bv2= F(t)+ C a first order equation. v'= (F(t)+ C Bv2)/A. How you would solve that would depend strongly on the form of F(t).

That's assuming that the differentiation is with respect to t. If it is with respect to x:
ELEN guy said:
The differentiation variable is NOT t, its just some other variable..lets say x
it's just dv/(F(t)+ C- Bv2)= Adx which is easy to integrate for each t.
 

Related to Please help Need solution to Second Order nonlinear DE

1. What is a Second Order Nonlinear Differential Equation (DE)?

A Second Order Nonlinear Differential Equation is a mathematical equation that involves the second derivative of a function, as well as other nonlinear terms such as powers, products, or functions of the dependent variable. These types of equations are commonly used in physics, engineering, and other fields to model complex systems.

2. Why is it important to find a solution to a Second Order Nonlinear DE?

Finding a solution to a Second Order Nonlinear DE allows us to understand the behavior of complex systems and make predictions about their future behavior. This can be useful in designing experiments, solving real-world problems, and making accurate forecasts.

3. What methods can be used to solve a Second Order Nonlinear DE?

There are several methods that can be used to solve a Second Order Nonlinear DE, including the substitution method, the power series method, and the Frobenius method. These methods involve manipulating the equation to reduce it to a simpler form, which can then be solved using standard techniques like integration or differentiation.

4. Are there any real-world applications of Second Order Nonlinear DEs?

Yes, there are many real-world applications of Second Order Nonlinear DEs. These include modeling population growth, predicting the behavior of electrical circuits, and understanding the dynamics of chemical reactions. They are also used in fields such as economics, biology, and meteorology to model complex systems.

5. Is there any software available to help solve Second Order Nonlinear DEs?

Yes, there is software available to help solve Second Order Nonlinear DEs. Some popular options include MATLAB, Mathematica, and Maple. These programs have built-in functions and algorithms specifically designed to solve differential equations and can handle complex and nonlinear equations with ease.

Similar threads

  • Calculus and Beyond Homework Help
Replies
7
Views
719
  • Calculus and Beyond Homework Help
Replies
2
Views
370
  • Calculus and Beyond Homework Help
Replies
5
Views
347
  • Calculus and Beyond Homework Help
Replies
6
Views
2K
Replies
4
Views
567
  • Calculus and Beyond Homework Help
Replies
21
Views
905
  • Calculus and Beyond Homework Help
Replies
3
Views
609
  • Calculus and Beyond Homework Help
Replies
2
Views
330
  • Calculus and Beyond Homework Help
Replies
8
Views
338
  • Calculus and Beyond Homework Help
Replies
2
Views
310
Back
Top