Photoelectric effect and free electrons

In summary: The metal will be charged unless it replaces the missing electron, but we don't say that the metal is ionized. That terms is usually reserved for single atoms and sometimes molecules.
  • #1
Docscientist
101
11
When we shine a light of particular color on a metal,it expells the free electrons present in the metal.In that case,doesn't the metal get ionized ?
 
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  • #2
Depends on what you exactly mean by ionization. You won't be able to point to ions. There are no isolated, charged atoms, rather every single atom misses a piece of an electron.
 
  • #3
Borek said:
There are no isolated, charged atoms, rather every single atom misses a piece of an electron.
Can you elaborate more on that ? And you say they "miss a piece of electron", why can't that be called ionisation ?
 
  • #4
Docscientist said:
Can you elaborate more on that ? And you say they "miss a piece of electron", why can't that be called ionisation ?
In a metal, the outermost electrons are delocalised rather than bound to an individual atom, so no single metal atom loses an electron.
 
  • #5
Vagn said:
In a metal, the outermost electrons are delocalised rather than bound to an individual atom, so no single metal atom loses an electron.
What do you mean by delocalised ?
 
  • #6
Docscientist said:
What do you mean by delocalised ?
Have you tried the wikipoedia page on delocalized electrons?
 
  • #7
Vagn said:
Have you tried the wikipoedia page on delocalized electrons?
I just went through the page.I still can't get it.Even if it is delocalized,it is still a free electron that once belonged to the metal's atoms.So any way there is a losing that takes place.In that case,considering the metal to be ionized should be right,isn't it ?
 
  • #8
Docscientist said:
I just went through the page.I still can't get it.Even if it is delocalized,it is still a free electron that once belonged to the metal's atoms.So any way there is a losing that takes place.In that case,considering the metal to be ionized should be right,isn't it ?

The metal will be charged unless it replaces the missing electron, but we don't say that the metal is ionized. That terms is usually reserved for single atoms and sometimes molecules.
 

Related to Photoelectric effect and free electrons

1. What is the photoelectric effect?

The photoelectric effect is the phenomenon where electrons are emitted from a material when it is exposed to electromagnetic radiation, such as light. This effect was first described by Albert Einstein in 1905 and has since been used in various applications, such as solar panels and photocells.

2. How does the photoelectric effect work?

The photoelectric effect occurs when photons from an incoming light beam strike the surface of a material with enough energy to knock electrons out of their atomic orbits. These electrons then become free to move, creating an electric current.

3. What determines the number of electrons released in the photoelectric effect?

The number of electrons released in the photoelectric effect depends on the intensity and frequency of the incoming light, as well as the properties of the material. Higher intensity and frequency of light result in a greater number of electrons being emitted.

4. What is the role of free electrons in the photoelectric effect?

Free electrons are essential in the photoelectric effect as they are the ones that are released from the material and contribute to the electric current. The energy of the free electrons is also dependent on the frequency of the incoming light.

5. Can the photoelectric effect be used to explain other phenomena?

Yes, the photoelectric effect has been used to explain other phenomena, such as the Compton effect and the dual nature of light. It has also been applied in the development of technologies like electron microscopes and photodetectors.

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