Partition Theory of Nitrigen to determine ther quantities (eg U, H, F)

In summary, for a mole of nitrogen gas at room temperature and atmospheric pressure, one can calculate the internal partition function, Z_1, using the formula Z_1 = Z_{int} = \sum{exp(-E_{int}(s)/k_BT)}, where the rotational constant for N2 is given as 0.00025 eV. The total partition function, Z_{total}, can then be calculated using the formula Z_{total} = \frac{1}{N!} (Z_1)^N, where N is the number of particles (1 mole). From there, one can use the equations U = -\frac{\partial}{\partial \beta} ln z, H = U + PV,
  • #1
TFM
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Homework Statement



For a mole of nitrogen (N2) gas at room temperature and atmospheric pressure, compute the following: U, H, F, G, S and μ. The internal partition function is purely rotational, and the rotational constant ε for N2 is 0.00025 eV. The electronic ground state is not degenerate.

Homework Equations



[tex] Z_{total} = \frac{1}{N!}_1^N [/tex]

[tex] Z_1 = Z_{int} = \sum{exp(-E_{int}(s)/k_BT)} [/tex]

[tex] U = -\frac{\partial}{\partial \beta} ln z [/tex]

The Attempt at a Solution



Okay, I am having a slight problem calculating the Z value. I have used:


[tex] Z_1 = Z_{int} = \sum{exp(-E_{int}(s)/k_BT)} [/tex]

and inserted 300 K, E = 0.00025 eV abd the Boltzmann Constant (in eV) into this, and have got 9.67 *10^{-3}

I now want to use:

[tex] Z_{total} = \frac{1}{N!}_1^N [/tex]

but N is the number of particles, which is 1 Mole x Avagadros Number. This leaves with a large number which I have to find the factorial of, but it is too large for Excel. Have I gone wrong somewhere?

TFM
 
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  • #2
:

Hello, thank you for your post. Your calculation for Z_1 looks correct. However, for Z_{total}, you do not need to calculate the factorial of Avogadro's number. Instead, you can use the formula:

Z_{total} = \frac{1}{N!} (Z_1)^N

where N is the number of particles (in this case, 1 mole), and Z_1 is the internal partition function that you calculated. This should give you a more manageable number for Z_{total}.

Once you have calculated Z_{total}, you can use the equations you listed to calculate U, H, F, G, S, and μ. I hope this helps! Let me know if you have any further questions.
 
  • #3
:

Thank you for your question. It seems like you are on the right track with your calculations. However, there are a few things to consider when using the partition function to determine quantities like U, H, F, G, S, and μ.

First, it is important to note that the partition function for a single molecule (Z1) is not the same as the total partition function (Ztotal). The Ztotal takes into account the number of molecules present, while Z1 only considers the internal states of a single molecule. So, when using Ztotal, you do not need to use the factor of N! in the equation.

Secondly, when calculating U, H, F, G, S, and μ, you will need to use the following equations:

U = -kBT^2\frac{\partial}{\partial T}(lnZtotal)

H = U + kBT^2\frac{\partial}{\partial T}(lnZtotal)

F = -kBTlnZtotal

G = U + PV - TS = F + PV

S = -\frac{\partial F}{\partial T}

μ = \frac{\partial F}{\partial N}

where P is the pressure, V is the volume, and N is the number of molecules.

So, to summarize, when using the partition function to determine quantities, make sure you are using the correct equations and taking into account the number of molecules present. I hope this helps. Good luck with your calculations!
 

Related to Partition Theory of Nitrigen to determine ther quantities (eg U, H, F)

1. What is Partition Theory of Nitrogen?

The Partition Theory of Nitrogen is a scientific theory that explains the behavior of nitrogen in different environments. It describes how nitrogen, as a diatomic gas, can be partitioned into different phases such as gas, liquid, and solid, depending on factors like temperature and pressure.

2. How does Partition Theory of Nitrogen determine quantities like U, H, and F?

The Partition Theory of Nitrogen uses thermodynamic principles to calculate the quantities of internal energy (U), enthalpy (H), and free energy (F) for nitrogen in different phases. These quantities are important for understanding the physical and chemical properties of nitrogen.

3. What are the key assumptions of Partition Theory of Nitrogen?

The Partition Theory of Nitrogen assumes that nitrogen behaves like an ideal gas, follows the laws of thermodynamics, and that intermolecular forces between nitrogen molecules are negligible. It also assumes that the nitrogen molecules are in thermal equilibrium with their surroundings.

4. How is Partition Theory of Nitrogen used in practical applications?

The Partition Theory of Nitrogen is used in a wide range of practical applications, such as in the design of chemical processes involving nitrogen, the production and storage of liquid nitrogen, and the study of atmospheric conditions on Earth and other planets.

5. Are there any limitations to the Partition Theory of Nitrogen?

While the Partition Theory of Nitrogen is a useful tool for understanding the behavior of nitrogen, it has some limitations. It does not take into account the effects of non-ideal behavior, such as the formation of nitrogen clusters, and it may not accurately predict the behavior of nitrogen at extremely high or low temperatures and pressures.

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