- #1
redshift
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As part of finding the integral of z/(z^2 -1), I'm stuck on getting the partial fraction for it. 1/2 [(1/(z-1) - 1/(z+1)] gives 1/(z^2-1). What should I do to get the z in the numerator. Any hints welcome.
Regards
Regards
Partial fraction of integrand is a method used in integration to simplify and break down a complicated rational function into smaller, more manageable fractions.
This method is useful because it allows for easier integration of complicated rational functions, making it easier to find the antiderivative and solve integrals.
To perform partial fraction of integrand, you must first factor the denominator of the rational function into linear or quadratic factors. Then, you must find the coefficients of each fraction by equating the expanded form of the rational function to the original form and solving for the unknown coefficients.
There are two types of partial fraction of integrand: proper and improper. Proper partial fractions have a degree of the numerator that is less than the degree of the denominator, while improper partial fractions have a degree of the numerator that is equal to or greater than the degree of the denominator.
Partial fraction of integrand should be used when integrating rational functions with complex or higher degree polynomials in the denominator, as it simplifies the process and makes it easier to integrate.