Optimizing Link Budget for 1.1km Transmission with 875MHz Carrier Frequency

In summary, a signal with a carrier frequency of 875MHz needs to be transmitted over a distance of 1.1km with a bandwidth of 12Hkz on FM carrier. The allowed carrier power for transmission and reception is 1W and the antennas have a low loss with a maximum attenuation of 0.1dB. The received power can be calculated using the equation Received Power (dBm) = Transmitted Power (dBm) + Gains (dB) − Losses (dB), where the losses can be calculated using the formula ((4*3.14*1100*875000000)/300000000)^2=FSPL and assuming a 0.1dB attenuation per antenna. This results
  • #1
Mickydawg25
7
0

Homework Statement


A signal needs to be transmitted over 1.1km, with 12Hkz bandwidth on FM carrier.
Carrier freq=875MHz.
Allowed up to 1W carrier power transmitted and received thru omnidirectional antennas.
antennas low loss, max attenuation = 0.1dB


Homework Equations



Received Power (dBm) = Transmitted Power (dBm) + Gains (dB) − Losses (dB)

The Attempt at a Solution



I'm beat
 
Last edited by a moderator:
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  • #2
Mickydawg25 said:

Homework Statement


A signal needs to be transmitted over 1.1km, with 12Hkz bandwidth on FM carrier.
Carrier freq=875MHz.
Allowed up to 1W carrier power transmitted and received thru omnidirectional antennas.
antennas low loss, max attenuation = 0.1dB


Homework Equations



Received Power (dBm) = Transmitted Power (dBm) + Gains (dB) − Losses (dB)

The Attempt at a Solution



I'm beat

Well, at least you listed a Relevant Equation. That's good.

Now, what can you fill into that equation? What are the losses for example?
 
  • #3
are the losses the free space path losses?
((4*3.14*1100*875000000)/300000000)^2

is the gain the attenuation ie G -0.1dB?

Power=1watt=30dB?
 
  • #4
Mickydawg25 said:
are the losses the free space path losses?
((4*3.14*1100*875000000)/300000000)^2

is the gain the attenuation ie G -0.1dB?

Power=1watt=30dB?

What is "875000000)/300000000"?

The gain would be any antenna gain, but you are told the radiation is isotropic, so there is no gain.

It looks like you are trying to calculate the loss by using the surface area of a sphere of 1100m radius, which is correct. The 0.1dB would be an additional antenna loss to add in.

1Watt is 1000 times 1mW, so yes, that would be 10*log(1W/1mW) = 30dBm.


EDIT -- BTW, the question does not make it clear if it is 0.1dB max loss per antenna or for the two antennas as a system. You should see if you can clarify that (it oly changes your answer by 0.1dB, but it would be good to get it right the first time).
 
  • #5
f=875000000
c=300000000

using ((4*pi*d*f)/c)^2=FSPL
((4*3.14*1100*875000000)/300000000)^2=FSPL

10log(FSPL)= losses in dB = 92.1dB

assuming 0.1dB attenuation per each antenna

Received Power (dBm) = Transmitted Power (dBm) + Gains (dB) − Losses (dB)
Pr=30dbm + 0 - 92.1dB - 0.2dB

Pr=-62.3dBm?
 

Related to Optimizing Link Budget for 1.1km Transmission with 875MHz Carrier Frequency

1. How do you calculate the link budget for a 1.1km transmission with a carrier frequency of 875MHz?

The link budget for a transmission can be calculated by adding up the gain and loss factors in the signal path. This includes factors such as antenna gain, cable loss, and atmospheric attenuation. The formula for link budget is:
Link Budget = Tx Power + Tx Antenna Gain - Cable Losses - Atmospheric Attenuation + Rx Antenna Gain - Rx Sensitivity.
For a 1.1km transmission with 875MHz carrier frequency, the specific gain and loss factors for each component must be determined and plugged into the formula to calculate the link budget.

2. How does the distance of the transmission affect the link budget?

The distance of the transmission can greatly impact the link budget as it directly affects the path loss. As the distance increases, the signal strength decreases, leading to a lower link budget. This is because the signal has to travel through more atmosphere, which causes attenuation, and also experiences more free space loss. Therefore, for a longer transmission distance, the link budget needs to be optimized with higher gain factors in order to maintain a strong and reliable signal.

3. What factors can affect the carrier frequency in a transmission?

The carrier frequency in a transmission can be affected by various factors such as interference, multipath propagation, and atmospheric conditions. Interference from other signals or sources can cause noise and affect the clarity of the carrier frequency. Multipath propagation occurs when the signal reflects off of objects in the environment, causing multiple signals to reach the receiver at different times. This can cause distortion and signal loss. Atmospheric conditions, such as rain or fog, can also affect the carrier frequency by causing attenuation and reducing the signal strength.

4. How can the link budget be optimized for a 1.1km transmission with 875MHz carrier frequency?

To optimize the link budget for this specific transmission, the gain and loss factors for each component need to be carefully selected and adjusted. This can include using high-gain antennas, choosing the right type of cable with low loss, and accounting for atmospheric conditions. The use of repeaters or amplifiers may also be necessary to boost the signal and improve the link budget. Additionally, proper positioning and alignment of antennas can also help optimize the link budget.

5. What is the significance of optimizing the link budget in a transmission?

Optimizing the link budget is crucial in ensuring a reliable and strong signal in a transmission. A higher link budget means a stronger signal, which leads to better data transmission and reception. This is especially important for long-distance transmissions, where the signal can easily weaken and become distorted. Optimizing the link budget also helps to minimize errors and reduce the need for retransmissions, leading to more efficient and effective data communication.

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