Optimizing Angle for Material Transfer System Efficiency

  • Thread starter physicsodyssey
  • Start date
  • Tags
    Angle
In summary, the system at duration 0:57 to 1:34 is designed to move parts around a circular track by using a counterweight and inclined tray. The angle of inclination is determined based on the hauling effect that the tray will have.
  • #1
physicsodyssey
11
6
I am trying to design a material transfer system ( the system at duration 0:57 to 1:34 ).
The general layout is http://i.imgur.com/ajQ05qy.png
It was suggested that angle be 5 degree. The reason is for hauling effect so the tray can revolve back. can you explain this? why 5 degrees? supporting references will be of great help.
Thank You.
 

Attachments

  • fzg.PNG
    fzg.PNG
    6.7 KB · Views: 413
Engineering news on Phys.org
  • #2
physicsodyssey said:
why 5 degrees?
Whatever inclination of the plane of the arm and counterweight is adequate to overcome the friction of the pivot bearing and yield a cycle time between loading and unloading the tray that is suitable for the process.
 
  • #3
There can be a range for it but how to approach it mathematically ?
Could you please elaborate it in detail? How would you approach the problem ? Do you need any data? m1=3kg & m2=10kg
I want to clear this concept and your help is highly appreciated.
 
  • #4
m 1 = Mass of empty pan in kg
Pw = Weight of parts in N
m 2 = Mass of counter weight needed to be attached in kg
θ = Angle of inclination of the conveyor track
x = Length of tray arm from axis of rotation in mm
y = Length of counter weight arm from axis of rotation in mm
a = Diameter of bearing housing in mm
Height of counterweight from datum = 900 mm
Height of pan from datum = 913 mm
x = Length of tray arm from axis of rotation in mm =1000mm
y = Length of counter weight arm from axis of rotation in mm = 300mm
m1=3kg(assumption)
m1(h + a sin θ) g x = m2 y h g
m2 = 3 x 900 x 913 /300 x 900 =9.13kg
How to proceed for assumption of θ?
Can you explain me the following equation?
Pwg ≥( m1 * x^2 + m 2 * y^2 ) sin2 θ / [ x(h-xsin2 θ)]
 
  • #5
physicsodyssey said:
Pwg ≥( m1 * x^2 + m 2 * y^2 ) sin2 θ / [ x(h-xsin2 θ)]
This is supposed to be giving you the minimum load (part weight) to unbalance the arm so it will swing and carry the part around the conveyor arc from station 1 to station 2 and hold it there. Unless the tray/pan and counterweight arms aren't 180 degrees opposed, there's no reason for that load to depend on the magnitude of theta other than that it be off vertical, so the form of the equation is somewhat arcane.

There isn't enough information to to calculate the speed of the movement, or the shock absorbing requirements at the ends of the travel range. Speed increases as theta increases, but without knowing particulars of bushings/bearings on the pivot, viscosities of lubricants, moments of inertia of the loaded and unloaded assembly there's no way of coming up with numbers.
 

Related to Optimizing Angle for Material Transfer System Efficiency

1. What is the "angle for hauling effect"?

The angle for hauling effect is a term used in physics and engineering to describe the optimal angle at which an object can be pulled or lifted in order to maximize the force or load that can be moved.

2. How is the angle for hauling effect calculated?

The angle for hauling effect can be calculated using trigonometry, specifically the sine function. The formula is: angle = sin^-1 (load/force), where load is the weight of the object being moved and force is the force applied to move it.

3. Why is it important to consider the angle for hauling effect?

Considering the angle for hauling effect is important because it allows for the most efficient use of force when moving objects. Using the correct angle can reduce the amount of force needed to move an object, making the task easier and more efficient.

4. What happens if the angle for hauling effect is incorrect?

If the angle for hauling effect is incorrect, it can result in a waste of energy and effort. Using an angle that is too steep or too flat will require more force to move an object, leading to inefficiency and potential strain on the equipment or person doing the hauling.

5. Can the angle for hauling effect be applied to different types of hauling tasks?

Yes, the angle for hauling effect can be applied to various hauling tasks, such as lifting objects with a pulley system, pulling objects with a rope, or pushing objects with a lever. The principle remains the same regardless of the specific task or equipment being used.

Similar threads

Replies
15
Views
2K
  • Mechanical Engineering
Replies
13
Views
1K
  • Mechanical Engineering
Replies
5
Views
2K
  • Mechanical Engineering
Replies
1
Views
995
Replies
5
Views
1K
Replies
7
Views
2K
  • Materials and Chemical Engineering
Replies
7
Views
2K
  • Mechanical Engineering
Replies
2
Views
3K
  • Computing and Technology
Replies
2
Views
722
  • Advanced Physics Homework Help
Replies
2
Views
1K
Back
Top