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- #1

#### Albert

##### Well-known member

- Jan 25, 2013

- 1,225

$\sqrt {x}+\sqrt {y}=35$

$\sqrt [3]{x}+\sqrt[3] {y}=13$

find x+y

$\sqrt [3]{x}+\sqrt[3] {y}=13$

find x+y

- Thread starter Albert
- Start date

- Thread starter
- #1

- Jan 25, 2013

- 1,225

$\sqrt {x}+\sqrt {y}=35$

$\sqrt [3]{x}+\sqrt[3] {y}=13$

find x+y

$\sqrt [3]{x}+\sqrt[3] {y}=13$

find x+y

- Feb 13, 2012

- 1,704

Setting $\displaystyle \varphi = x^{\frac{1}{6}}$ and $\displaystyle \psi = y^{\frac{1}{6}}$ You obtain...$\sqrt {x}+\sqrt {y}=35$

$\sqrt [3]{x}+\sqrt[3] {y}=13$

find x+y

$\displaystyle \varphi^{3} + \psi^ {3} = 35$

$\displaystyle \varphi^{2} + \psi^ {2} = 13$ (1)

... and the (1) has solutions $\displaystyle \varphi=2\ \psi= 3$ and $\displaystyle \varphi=3\ \psi= 2$ so that is in any case $\displaystyle \varphi + \psi = 5$...

Kind regards

$\chi$ $\sigma$

- Admin
- #3

- Mar 5, 2012

- 9,805

Setting $\chi = \varphi^6$ and $\sigma = \psi^6$, we get $\chi + \sigma = \varphi^6 + \psi^6 = 2^6 + 3^6 = 793$.

Kind regards,

$\text{I}\Lambda\Sigma$