- #1
mogul
- 2
- 0
Hi,
please help me with this task. I'm wondering what is the right result.
I have a ODE
[itex]y'' - b^2 y =0[/itex]
also the result should be
[itex]y=C e^{\pm bx}[/itex]
but what is the result when b is vector?
[itex]\vec b=(b_x, b_y)[/itex]
is this the result?
[itex]y=C e^{\pm \vec{b}x}[/itex]
or this?
[itex]y=C e^{\pm |b| x}[/itex]
how to solve it?
thanks for help!
please help me with this task. I'm wondering what is the right result.
I have a ODE
[itex]y'' - b^2 y =0[/itex]
also the result should be
[itex]y=C e^{\pm bx}[/itex]
but what is the result when b is vector?
[itex]\vec b=(b_x, b_y)[/itex]
is this the result?
[itex]y=C e^{\pm \vec{b}x}[/itex]
or this?
[itex]y=C e^{\pm |b| x}[/itex]
how to solve it?
thanks for help!