Nuclear physics Pions and Parity?

[Davorak]

Nuclear physics Pions and Parity? Ignore, nevermind

Why can:
[tex]
\pi^- + d \rightarrow n + n + \pi^0
[/tex]
not happen for pions at rest?

work so far:
[tex]
\begin{array}
{|c|c|c|c|c|c|}\hline&\pi^-&d&\rightarrow &n \ + \ n&\pi^0\\\hline{Spin}&0&1&\
\rightarrow &1/2 \ 1/2&0\\\hline{J}&0&1&\rightarrow &L + \
S&0\\\hline{Parity}&-1&1&\rightarrow &(-1)^{S+L+1}&-1\\\hline
\end{array}
[/tex]
d is deuterium
S+L for the nuetron pair must be even since they are identical fermions
Partity egeinvalues -1 != 1
I think the Paritiy inequality is the key, but i can not make the connection with a physical law.
Any help would be nice, Thanks

Edit: never mind I figuared it out. Aditional angular momentum on the left hand side will flip parity(l=1,3,5...), making parity conserved again. Thanks anyway

 

[anathema]

I would like to advise you to ignore this question and move on to more relevant and meaningful topics in nuclear physics. The concept of pions and parity is not a current area of research and has been extensively studied and understood in the past. It is important to focus on current and relevant research in order to make progress in the field.

 

[wais]

.

Thank you for sharing your thought process and solution. It is great to see that you were able to figure it out on your own. Keep up the good work!