- #1
phosgene
- 146
- 1
Homework Statement
I need to find the normalization constant [itex]N_{S}[/itex] of a symmetric wavefunction
[itex]ψ(x_{1},x_{2}) = N_{S}[ψ_{a}(x_{1})ψ_{b}(x_{2}) + ψ_{a}(x_{2})ψ_{b}(x_{1})][/itex]
assuming that the normalization of the individual wavefunctions [itex]ψ_{a}(x_{1})ψ_{b}(x_{2}), ψ_{a}(x_{2})ψ_{b}(x_{1})[/itex] are both just 1 and not orthogonal.
Homework Equations
For a symmetric wavefunction [itex]ψ_{a}(x_{1})ψ_{b}(x_{2}) = ψ_{a}(x_{2})ψ_{b}(x_{1})[/itex]
3. Attempt at solution
I do the normalization and get [itex]N_{S}^2∫_{-∞}^{∞} 2 {|ψ_{a}(x_{1})ψ_{b}(x_{2})|}^{2} + ψ*_{a}(x_{1})ψ*_{b}(x_{2})ψ_{a}(x_{2})ψ_{b}(x_{1}) + ψ*_{a}(x_{2})ψ*_{b}(x_{1})ψ_{a}(x_{2})ψ_{b}(x_{1})dx_{1}dx_{2}=1[/itex]
Now, since the wavefunctions are symmetric, [itex]ψ*_{a}(x_{1})ψ*_{b}(x_{2})ψ_{a}(x_{2})ψ_{b}(x_{1}) = ψ*_{a}(x_{2})ψ*_{b}(x_{1})ψ_{a}(x_{2})ψ_{b}(x_{1})[/itex]
Since the answer is supposed to be [itex]N_{S}=1/\sqrt{2}[/itex], I'm guessing that [itex]ψ*_{a}(x_{1})ψ*_{b}(x_{2})ψ_{a}(x_{2})ψ_{b}(x_{1}) = 0[/itex], but I don't know why this would be.