New Energy Levels for Degenerate Perturbation Theory

In summary, the conversation discusses the e-states and e-values of H^0, which are affected by a perturbation H'. The new energy levels are calculated using first and second-order perturbation theory for non-degenerate cases, and first degenerate perturbation theory for degenerate cases. The equations used for these calculations are also mentioned.
  • #1
ma18
93
1

Homework Statement



The e-states of H^0 are

phi_1 = (1, 0, 0) , phi_2 = (0,1,0), phi_3 = (0,0,1) *all columns
with e-values E_1, E_2 and E_3 respectively.

Each are subject to the perturbation

H' = beta (0 1 0
1 0 1
0 1 0)

where beta is a positive constant

a) If E_1 =/ E_2 =/ E_3

What are the new energy levels according to first and second-order perturbation theory

b) If E_1 = E_2 = E_3

What are the new energy levels according to first degenerate perturbation theory

c) If E_1 =/ E_2 = E_3

What are the new energy levels according to first perturbation theory

Homework Equations



For first order non degenerate perturbation:

E_n ^1 = <phi_n ^ 0 | H' | phi_n ^ 0>

For second order perturbation

E_n ^2 = Σ (m=/n) of (|phi_m ^0 | H' | phi_n ^ 0>|^2)/(E_n ^ 0 - E_m ^0)

The Attempt at a Solution



a)

E_1 ^1 = < (1 | H' | (1 >
0 0
0) 0)

I am not sure how to deal with this as I just get zeroAny help pushing me in the right direction would be appreciated
 
Last edited:
Physics news on Phys.org
  • #2
Getting a zero only means that the first order correction to the energy vanishes. You should comtinue with the eigenstate perturbation and the second order energy correction.
 
  • #3
Ok, thanks I have figured out a) but am still have trouble with the degenerate case
 
  • #4
Can you show what you have attempted for the degenerate case?
 

Related to New Energy Levels for Degenerate Perturbation Theory

What is a Perturbation Hamiltonian?

A Perturbation Hamiltonian is a mathematical model used in quantum mechanics to describe the behavior of a system that is being influenced by an external force or perturbation. It is an extension of the original Hamiltonian, which describes the system in the absence of any external influences.

How is a Perturbation Hamiltonian used in quantum mechanics?

In quantum mechanics, the Perturbation Hamiltonian is used to calculate the changes in the energy levels and other properties of a system due to an external perturbation. It is an important tool in studying the behavior of atoms, molecules, and other quantum systems under the influence of external forces.

What is the difference between a Perturbation Hamiltonian and the original Hamiltonian?

The Perturbation Hamiltonian takes into account the influence of an external force or perturbation, while the original Hamiltonian describes the system in the absence of any external influences. The Perturbation Hamiltonian is an extension of the original Hamiltonian, and is used to calculate the changes in the system's properties due to the external influence.

What are some examples of external forces or perturbations that can be described by a Perturbation Hamiltonian?

Some examples of external forces or perturbations that can be described by a Perturbation Hamiltonian include electric and magnetic fields, collisions with other particles, and changes in the shape or structure of the system.

How is a Perturbation Hamiltonian solved?

The Perturbation Hamiltonian is typically solved using perturbation theory, which involves expanding the Hamiltonian in a series of terms and calculating the corrections to the system's properties at each order. This method is useful for systems where the perturbation is small compared to the original Hamiltonian.

Similar threads

  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
13
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
827
  • Atomic and Condensed Matter
Replies
0
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Quantum Physics
Replies
1
Views
792
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
5
Views
2K
Replies
10
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
4K
Back
Top