Neutron activation question

[cortiver]

Homework Statement

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(From a past exam paper)
Na-24 can be produced by irradiation of 27-Al with energetic neutrons. It decays by beta emission.

An aluminium sample of mass m=0.2g was irradiated by energetic neutrons for a period of 1 hour. Two hours after the end of irradiation the total 24-Na activity of the sample was 295 Bq.
(i) Calculate the total number of Na-24 nuclei that were present in the aluminium sample immediately at the end of the irradiation.
(ii) What was the neutron flux (use a reaction cross-section of [tex]\sigma[/tex]=0.125 barns).

Homework Equations

Basically, when the sample is being irradiated the number of 24-Na atoms [tex]N^{*}[/tex] obeys
[tex]\frac{dN^{*}}{dt} = R - \lambda N^{*}[/tex]
where [tex]R = N\sigma \Phi[/tex] is the rate of neutron absorption, [tex]N[/tex] is the number of atoms in the sample, [tex]\sigma[/tex] is the microscopic cross-section, and [tex]\Phi[/tex] is the neutron flux. [tex]\lambda[/tex] is the decay constant. Once the irradiation is stopped, it decays according to
[tex]\frac{dN^{*}}{dt} = -\lambda N^{*}[/tex].

The Attempt at a Solution

It seems to be just a simple plug-and-chug question based on the rudimentary treatment of neutron activation analysis that we did in class, but the thing is that I can't see how you can possibly do it without knowing the Na-24 half-life and the atomic mass of aluminium, and neither of these values were given anywhere in the exam paper. Am I missing something obvious here?

 

[Astronuc]

The atomic mass of Al-27 is 27 amu. To go from ²⁷Al to ²²Na requires an (n,α) reaction.

The half-life of Na-22 is 14.951 hrs. One reference is http://www.nndc.bnl.gov/chart/.

However, since A = λ N, then is it possible to determine λ, from the information given?

 

[cortiver]

Thank you for your answer.

The atomic mass of Al-27 is 27 amu. To go from ²⁷Al to ²²Na requires an (n,α) reaction.

You're right, I didn't realize that the mass defects are so small that you can just ignore them for these purposes.

The half-life of Na-22 is 14.951 hrs. One reference is http://www.nndc.bnl.gov/chart/.

But the point is, this question was in a past exam paper. That reference would not have been available.

However, since A = λ N, then is it possible to determine λ, from the information given?

But we don't know N either, since the neutron flux is unknown.