- #1
semc
- 368
- 5
From what i know if a graph has say one turning point, the relative global max(/min) is that point depending on the concavity correct? However as i was going through some notes, i notice that according to the mean value theorem that in a closed and bounded interval there exist a relative global max/min. Does that mean so long the interval is close and bounded, there will be a global max/min and it does not need to be the highest/lowest point in the graph? Let's say for a simple graph 1/x the global min will be x=0 and no global max? So if the interval is [2,5] is the global max and global min at x=5 and x=2 respectively? Thanks