- #1
ineedsomephys
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Ok so I have a flashlight that is 19.2 volts. It used to have a bulb that was 19.2 volts and .6 amps, but I broke it, and couldn't find a replacement, so I decided to try to use an LED and a resistor. The LED is 20 mA (.02 Amps) and 3.5 Volts. If I am correct, to find the resistor I need I would use:
(Vsupply - Vneeded) / Ineeded = Resistance
So
(19.2V - 3.5V) / .02A = 785 Ohms (or 800 to round up for safety)
Is this right? Thanks
(Vsupply - Vneeded) / Ineeded = Resistance
So
(19.2V - 3.5V) / .02A = 785 Ohms (or 800 to round up for safety)
Is this right? Thanks