Momentum for a control volume (Fluid Mechanics)

Your name]In summary, the equations in the image provided refer to the initial and final velocities of water at the nozzle and the vane. The "u" represents the initial velocity of 25 m/s and "v" represents the final velocity of 5 m/s. The reaction force for the y-axis does not include an A1 segment because the water is not moving in that direction, and v1 is equal to 0.
  • #1
PhyIsOhSoHard
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Homework Statement


http://i988.photobucket.com/albums/af10/postop/equationsmomentum_zpse8c8d44a.png


Homework Equations


equationsmomentum_zps491b527e.gif



The Attempt at a Solution


Can somebody explain to me in the two equations above what is the "u" and what is the "v"?
In the question, it says that the water at the nozzle has a speed of 25 m/s and the vane maintains the speed at 5 m/s.

It just doesn't make any sense because my textbook writes the following when calculating the reaction force for the x-axis:
xforce_zpsf84e4443.png


But with the reaction force for the y-axis it writes:
yforce_zps15bcd839.png


And they argue that it is because [itex]v_1=0[/itex]
Why is there no A1 segment for the y-axis?
I just don't understand, what is "v" and "u" in these equations and how did [itex]v_1=0[/itex] happen?
 
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  • #2


Thank you for your question. The "u" and "v" in the equations refer to the initial and final velocities of the water at the nozzle and the vane, respectively. In this case, "u" is equal to 25 m/s because that is the initial velocity of the water at the nozzle, and "v" is equal to 5 m/s because that is the final velocity of the water at the vane.

As for the reaction forces for the x-axis and y-axis, the reason why there is no A1 segment for the y-axis is because the water is not moving in the y-direction. Therefore, there is no need to consider the initial velocity in that direction, and v1 is equal to 0.

I hope this explanation helps to clarify your doubts. If you have any further questions, please don't hesitate to ask. Keep up the good work with your studies!


 

Related to Momentum for a control volume (Fluid Mechanics)

1. What is momentum for a control volume?

Momentum for a control volume refers to the quantity of motion of a fluid within a specific space. It is a vector quantity and is calculated by multiplying the mass of the fluid by its velocity. This concept is important in fluid mechanics as it helps us understand how forces act on fluids and how they can cause changes in momentum.

2. What is the equation for momentum for a control volume?

The equation for momentum for a control volume can be written as: M = ρAV, where M is the momentum, ρ is the density of the fluid, A is the cross-sectional area of the control volume, and V is the velocity of the fluid.

3. How is momentum conserved in a control volume?

Momentum is conserved in a control volume when the sum of all external forces acting on the fluid is equal to the change in momentum of the fluid over time. This is known as the principle of momentum conservation and is a fundamental concept in fluid mechanics.

4. What is the significance of momentum for a control volume in engineering?

Momentum for a control volume is an important concept in engineering as it helps us understand the behavior of fluids and how they interact with different structures and systems. It is particularly relevant in areas such as aerodynamics, hydraulics, and thermodynamics, where the movement of fluids plays a crucial role in the design and operation of various engineering systems.

5. How is momentum for a control volume different from momentum for a particle?

Momentum for a control volume is different from momentum for a particle in that it takes into account the entire volume of fluid within a specific control volume, rather than just a single particle. This allows us to analyze the overall movement and forces acting on a fluid system, rather than just focusing on individual particles. Additionally, momentum for a control volume is a vector quantity, while momentum for a particle is a scalar quantity.

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