- #1
Pushoam
- 962
- 51
If I consider a system of only two coins, then there are four microstates, each equally probable.
But the probability that the system will have one head and one tail is the most.
Describing the system by its all possible configurations is describing it in terms of its microstates.
Here, the microstates does't correspond to a given macrostate.
There are three macrostates: 1) 2H 2)1H and 1 T 3) 2T.
The microstates ( each of these is equally probable) corresponding to the macrostate 1H and 1T is maximum i.e.2. Hence, this macrostate is more probable.
Hence, the microstates whether it belong to a given macrostate or not are always equally probable.
But macrostates are not always equally probable.
Is my understanding correct?