me with this force problem, Thank you

In summary, the conversation discusses a 70 kg crate being pushed up a frictionless 23° incline at constant speed. The first question asks for the required horizontal force, which is found to be 246.73 N using the equation wsin(23)cos(23). The second question asks for the force exerted by the ramp on the crate, which is calculated to be 631 N by using the equation Wcos(23). The solution also involves identifying all the forces acting on the crate and writing two equations, one for force components parallel to the incline and the other for components perpendicular.
  • #1
Leocardinal
2
0

Homework Statement



A 70 kg crate is pushed at constant speed up the frictionless 23°

What horizontal force F is required? ( x Component Force)?

What force is exerted by the ramp on the crate?




Homework Equations



I used wsin(23) then i did (wsin(23))cos(23) which i found 246.73 N

and I used Wcos(23)= 631 N

I know that Fnet= 0 since the Velocity is constant acceleration is zero

I did a freebody Diagram



The Attempt at a Solution



I got 246.7 N for force in the Horizontal direction

and I got 631 N for what the second question is asking for.

I did that by calculating the Normal force.

Please Help
 
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  • #2
It's a bit hard to tell what you did. Start by identifying all the forces acting on the crate. Then write two equations: One for force components parallel to the incline; the other for components perpendicular.
 
  • #3


I would like to commend you on your efforts in solving this force problem. Your use of the equations and free body diagram are correct, and your answers for the horizontal force and the force exerted by the ramp on the crate are also correct. Good job!

However, I would like to suggest an alternative method for finding the horizontal force. Instead of using the weight of the crate (W), you can use the formula F = ma (force equals mass times acceleration). Since the crate is moving at a constant speed, its acceleration is zero, so the horizontal force needed to push it up the ramp is also zero. This means that the horizontal force is equal to the force of the ramp pushing back on the crate, which is the normal force (N) calculated as 631 N. So, the horizontal force required is also 631 N.

Overall, excellent job in solving the problem and using the correct equations and concepts. Keep up the good work!
 

Related to me with this force problem, Thank you

1. What is the force problem that you are facing?

The force problem refers to a situation where an object is being acted upon by one or more forces, and the goal is to find the resulting net force on the object.

2. How do you calculate the net force in a force problem?

The net force is calculated by adding all the individual forces acting on an object, taking into account their direction and magnitude. This can be done using vector addition or by using Newton's second law of motion (F=ma).

3. Can you give an example of a force problem?

An example of a force problem could be a car being pushed by two people in opposite directions. In this case, the net force on the car would be the sum of the forces applied by each person, and the direction of the net force would depend on which person is applying a greater force.

4. What are the units of force in a force problem?

The SI unit of force is the Newton (N), which is equivalent to kg*m/s^2. Other common units of force include pounds (lb) and dynes (dyn).

5. How can I solve a force problem if I don't know the mass of the object?

If the mass of the object is not given, you can still solve the force problem by using Newton's second law of motion (F=ma). In this case, the mass will cancel out and you will be left with the net force in units of N.

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