Max speed perpendicular to the wave's direction

In summary, the question asks for the maximum speed perpendicular to the direction of a wave's travel, using the given function y(x,t)=2sin(4x-2t). The book's hint is to find the amplitude of dy/dt, which is 2cos(4x-2t). However, the attempt at a solution is incorrect as it forgets to apply the chain rule of differentiation and assumes x=0 instead of solving for the maximum value of 2.
  • #1
Bsky
1
0

Homework Statement


This question is part of a longer problem. I know the answer, but I don't know how they got their. Please provide a detailed explanation. Thanks.

Question: Find the maximum speed perpendicular to the wave's direction of travel (the transverse speed).

y(x,t)=2sin(4x-2t)

Homework Equations


The book gives a hint: find amplitude of dy/dt. Therefore, dy/dt=2cos(4x-2t)



The Attempt at a Solution


Period= pi
Lambda= pi/2
Frequency= 1/pi
v=1/2
 
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  • #2
Bsky said:

y(x,t)=2sin(4x-2t)

Homework Equations


The book gives a hint: find amplitude of dy/dt. Therefore, dy/dt=2cos(4x-2t)

Incorrect. You forgot to apply the chain rule of differentiation.
 
  • #3
here u have to take x=0 as u r considering the perpendicular velocity. So once u assume that differentiate it and then u will get the max. value
 

Related to Max speed perpendicular to the wave's direction

1. What is the "Max speed perpendicular to the wave's direction"?

The "Max speed perpendicular to the wave's direction" refers to the maximum velocity that a particle or object can travel in a direction perpendicular to the direction of a wave. It is an important concept in understanding the behavior of waves and the motion of particles within a wave.

2. How is the "Max speed perpendicular to the wave's direction" calculated?

The "Max speed perpendicular to the wave's direction" can be calculated using the formula v = ωA, where v is the maximum velocity, ω is the angular frequency of the wave, and A is the amplitude of the wave. This formula applies to transverse waves, which have a perpendicular direction of motion.

3. Is the "Max speed perpendicular to the wave's direction" the same for all types of waves?

No, the "Max speed perpendicular to the wave's direction" can vary depending on the type of wave. For example, in electromagnetic waves, the maximum velocity is equal to the speed of light, while in mechanical waves such as water waves, the maximum velocity is determined by the properties of the medium the wave is traveling through.

4. How does the "Max speed perpendicular to the wave's direction" affect the behavior of a wave?

The "Max speed perpendicular to the wave's direction" is a key factor in determining the amplitude and wavelength of a wave. It also affects how the wave interacts with objects and how energy is transferred through the wave. In general, higher maximum velocities result in stronger and more energetic waves.

5. Can the "Max speed perpendicular to the wave's direction" be exceeded?

No, the "Max speed perpendicular to the wave's direction" cannot be exceeded. This is because the maximum velocity is determined by the properties of the medium and the frequency of the wave. If the maximum velocity is exceeded, it can lead to distortion or destruction of the wave.

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