- #1
Panphobia
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- 13
Homework Statement
Max/min of f(x, y) = 1/x + 1/y
Constraint 1/x^2 + 1/y^2 = 1
The Attempt at a Solution
This was a question on my midterm exam and I am just wondering what the right answer would be.
With lagrange multipliers, I got two candidate points (sqrt (2), sqrt (2)) and (-(sqrt (2),-sqrt (2)) then I did what the prof taught in class and I checked the end behaviour, I concluded that as either x or y go to infinity or negative infinity, the other variable goes to 1, now I wrote that there is no max or min, but I know I'm not right, what is the right answer and how would I get it?