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Sixty3
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Homework Statement
Two spaceships A and B are launched from a point X, in opposite directions.
At time t=15 minutes, spaceship A crashes.
The velocity of the spaceships relative to X is 1.3x10⁸m/s.
How far did the collision happen from B, as observed by astronauts on the spaceship?
Homework Equations
x'=ɣ(x-vt)
x=vt
The Attempt at a Solution
I've calculated ɣ to be 1.11
The distance from spaceship A to the point X is 1.17x10¹¹m, so the distance from point B to x is also 1.17x10¹¹m.
x'=ɣ(x-vt)
x'=1.11(2*1.17x10¹¹-1.3x10⁸(60*15))
x'=1.30x10¹¹m
So the distance is 2(1.17x10¹¹)+1.30x10¹¹=3.64x10¹¹m.
I am probably using the equations incorrectly, so if anyone could help me out, it will be appreciated.