Looking for some intuition on a basic Algebra equation

In summary, the conversation discusses the concept of clearing decimals in equations, specifically when multiplying the denominator of the decimal with the greatest decimal places by both sides of the equation. The book suggests not to multiply the other factor, in this case (50-x), by 10 as well, as it would essentially be multiplying the left side by 100. This is due to the fact that there is no distributive law for multiplication over multiplication. The conversation also mentions the importance of understanding the underlying concepts in Algebra 1, such as properties of numbers, equality, and inequality, as well as developing logical thinking when dealing with inequalities and absolute values. It is noted that these skills may be difficult for students at first, but with repeated and intensive study
  • #1
DS2C
This isn't for math homework. I'm in self study and came across something in my book that I'm seeking clarification for.

The equation:
$$0.3\left(50-x\right)=6$$
The solution:
$$3\left(50-x\right)=60$$
$$150-3x=60$$
$$-3x=-90$$
$$x=30$$

Simple enough. My question is in regards to this:
The book says when clearing decimals, to multiply the denominator of the decimal with the greatest decimal places by both sides of the equation. Clearly that is done here, but why don't we multiply the ##\left(50-x\right)## by 10 as well? I would think that in multiplying each side of the equation by 10 would mean multiply each factor of each side of the equation by 10.
 
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  • #2
DS2C said:
This isn't for math homework. I'm in self study and came across something in my book that I'm seeking clarification for.

The equation:
$$0.3\left(50-x\right)=6$$
The solution:
$$3\left(50-x\right)=60$$
$$150-3x=60$$
$$-3x=-90$$
$$x=30$$

Simple enough. My question is in regards to this:
The book says when clearing decimals, to multiply the denominator of the decimal with the greatest decimal places by both sides of the equation. Clearly that is done here, but why don't we multiply the ##\left(50-x\right)## by 10 as well? I would think that in multiplying each side of the equation by 10 would mean multiply each factor of each side of the equation by 10.
No.
Multiplying the left side by 10, you can multiply either the .3 factor or the 50 - x factor, but not both factors. If you multiplied both factors on the left side, you would essentially be multiplying the left side by 100.

There is no distributive law for multiplication over multiplication. In other words, it's not true that a(bc) = (ab)(ac). More concretely, for 3(5 * 2) you can expand this as 15 * 2 or as 5 * 6, both of which simplify to 30, but you can't rewrite it as 15 * 6, which is 90..
 
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  • #3
Makes total sense. Didnt think of it like that. Thank you sir.
 
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  • #4
DS2C

The main idea in Algebra 1 is Properties of Numbers, Properties of Equality, Properties of Inequality. You learn how numbers work, including using some graphical ways to help understand. If this main idea is in-line with your way of thinking, or if you can develop this through study, then you will find that some of or much of Algebra 1 will become intuitive (more or less).
 
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  • #5
Thank you that's very helpful. I've been working on being able to understand the whys and hows of all the problems to give me a good understanding of the underlying concepts and I think its been really helpful so far. I used to just memorize how to solve a problem but I've noticed that if I understand it makes it easier to solve any problem in general, not just that specific one.
Sometimes I think myself into a hole like in this
situation so I come here for help and I appreciate when members throw me a line.
 
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  • #6
DS2C said:
Thank you that's very helpful. I've been working on being able to understand the whys and hows of all the problems to give me a good understanding of the underlying concepts and I think its been really helpful so far. I used to just memorize how to solve a problem but I've noticed that if I understand it makes it easier to solve any problem in general, not just that specific one.
Sometimes I think myself into a hole like in this
situation so I come here for help and I appreciate when members throw me a line.
You also have some logical thinking to develop, like when dealing with inequalities or absolute values.
 
  • #7
symbolipoint said:
You also have some logical thinking to develop, like when dealing with inequalities or absolute values.
That's definitely true. In general I need to develop pretty much every skill related to math. Never really cared in high school and its been 9 years so I am starting from scratch. Really liking it.
 
  • #8
symbolipoint said:
You also have some logical thinking to develop, like when dealing with inequalities or absolute values.
DS2C said:
That's definitely true. In general I need to develop pretty much every skill related to math. Never really cared in high school and its been 9 years so I am starting from scratch. Really liking it.
Those are what bring variable expressions, drawing, and logic together. One should draw situations on a numberline, and ask TRUE-FALSE questions and solve accordingly. This can be difficult for the Algebra 1 and Algebra 2 students; but this stuff does become easier upon repeated study (or longer more intensive study).
 
  • #9
symbolipoint said:
Those are what bring variable expressions, drawing, and logic together. One should draw situations on a numberline, and ask TRUE-FALSE questions and solve accordingly. This can be difficult for the Algebra 1 and Algebra 2 students; but this stuff does become easier upon repeated study (or longer more intensive study).

What do you mean by the first two sentences? Could you give me an example? This is good stuff.
 

Related to Looking for some intuition on a basic Algebra equation

1. What is the basic Algebra equation?

The basic Algebra equation is an equation that contains one or more variables and is used to solve for unknown values by manipulating the given information using algebraic operations.

2. How do I solve a basic Algebra equation?

To solve a basic Algebra equation, you need to isolate the variable on one side of the equation by using inverse operations. This means that you perform the opposite operation on both sides of the equation until the variable is separated on one side and the constant value is on the other side.

3. What are the algebraic operations used in solving an equation?

The algebraic operations used in solving an equation include addition, subtraction, multiplication, division, and exponentiation. These operations are used to manipulate the given information and isolate the variable to solve for its value.

4. How do I check if my solution is correct?

You can check if your solution is correct by substituting the value you have obtained for the variable back into the original equation. If both sides of the equation still balance, then your solution is correct.

5. What are some tips for solving Algebra equations?

Some tips for solving Algebra equations include carefully reading and understanding the given information, using inverse operations, simplifying the equations before solving, and checking your solution. It is also helpful to practice solving different types of equations to improve your skills.

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