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svasudevan
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Standard Matrix for R^3 -> R^4 where if domain is Linearly Independent so is codomain
5. Suppose T : R^3 -> R^4 is a linear transformation with the following property:
For any linearly independent vectors v_1, v_2 and v_3 in R^3, the images T(v_1),
T(v_2) and T(v_3) are linearly independent in R4.
(a) Give an example of such a linear transformation. Give its standard matrix and the
reduced row echelon form of this matrix.
(b) Work out all possible shapes of the reduced row echelon form for such a matrix.
Use the symbols 0, 1, and * where * indicates an entry which may take on the value
of any real number.
No relevant equations. The linear transformation must be given as a standard matrix with dimensions 3 * 4 since that would lead to a vector in R^4.
So far I know that since the vectors are linearly independent, the reduced form of both vectors must have pivots in each column. I reasoned that the function must be injective because each vector in R^3 can only correspond to 1 vector in R^4 but there are more vectors in R^4 than R^3.
This question seems confusing and I can't put my thoughts together. This is not a very advanced class (it is just a standard freshman linear algebra course for scientists and scientists).
Homework Statement
5. Suppose T : R^3 -> R^4 is a linear transformation with the following property:
For any linearly independent vectors v_1, v_2 and v_3 in R^3, the images T(v_1),
T(v_2) and T(v_3) are linearly independent in R4.
(a) Give an example of such a linear transformation. Give its standard matrix and the
reduced row echelon form of this matrix.
(b) Work out all possible shapes of the reduced row echelon form for such a matrix.
Use the symbols 0, 1, and * where * indicates an entry which may take on the value
of any real number.
Homework Equations
No relevant equations. The linear transformation must be given as a standard matrix with dimensions 3 * 4 since that would lead to a vector in R^4.
The Attempt at a Solution
So far I know that since the vectors are linearly independent, the reduced form of both vectors must have pivots in each column. I reasoned that the function must be injective because each vector in R^3 can only correspond to 1 vector in R^4 but there are more vectors in R^4 than R^3.
This question seems confusing and I can't put my thoughts together. This is not a very advanced class (it is just a standard freshman linear algebra course for scientists and scientists).
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