- #1
Felafel
- 171
- 0
Homework Statement
I have done this exercise, but I don't have a file with the solutions. COuld you please check it?
Thank you in advance :)
Given the following system:
##\lambda \in \mathbb{R}##
##x − z = \lambda##
##x + y + 2z + t = 0 ##
##y + 3z = ##
##x + z + t = 0##
1-find ##rk(A_{\lambda}) and rk(A_{\lambda}, B_{\lambda})## according to the different values of ##\lambda##
2- for which values of ##\lambda## does tha system have solutions?
3- what is its solutions set?
4- for which values is the system homogeneous ?
The Attempt at a Solution
This is the matrix ##(A_{\lambda}, B_{\lambda})##
( 1 0 1 -1 λ)
( λ 1 2 1 0)
( 0 1 3 0 λ)
( 1 0 1 λ 0)
doing some row reduction i get:
( 1 0 -1 0 λ )
( 0 0 2 λ -λ )
(λ-1 0 0 1 -2λ)
( 0 1 3 0 λ)
and i see rk(A)=rk(A,B) for any ##\lambda##, so according to Rouchè-Capelli's theorem the system has solutions.
So, answers to 1 and 2 are: 1- rk(A)=rk(A,B) for any ##\lambda \in \mathbb{R}## 2-##\forany \lambda \in \mathbb{R}##
Now, if ##\lambda##=1 i get:
(1 0 -1 0 1)
(0 0 2 1 -1)
(0 0 0 1 -2)
(0 1 3 0 1) thus: x=3/2, y= -1/2, z=1/2, t=-2 is the only solution
Doing the same, if ##\lambda##=0 i get (x, y, z, t)=(0, 0, 0, 0)
(IS IT ACCEPTABLE AS A SOLUTION?)
If ##\lambda## is different from 0 and 1,
x-z=##\lambda##
2z+λt=-λ
(λ-1)x+t=-2λ
3z+y=λ
with z= ##\alpha##
##\Sigma##: (x,y,z,t)= (λ+##\alpha##, λ-3 ##\alpha, \alpha, \frac{-λ-2\alpha}{λ}##)
so answer to nu,ber 3: the solutions sets are those above
4- the system is homogeneous for λ=0. for its solutions set, see above.